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mr Goodwill [35]
3 years ago
9

Plz answer the question

Mathematics
2 answers:
IgorC [24]3 years ago
8 0
1/6 of 30 is 5 questions. Combine 1/5 of the questions with it which is another 6 so she got 11 questions wrong. The answer is 19
Bumek [7]3 years ago
3 0
24 were of the questione were correct
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These 12 shapes are put into a bag. If you reach
Svetlanka [38]
25 times :) hope this helped!
3 0
2 years ago
Evaluate the following double integral where a = 2y
Keith_Richards [23]

Change the order of integration.

\displaystyle \int_0^1 \int_{2y}^2 \cos(x^2) \, dx \, dy = \int_0^2 \int_0^{x/2} \cos(x^2) \, dy \, dx \\\\ ~~~~~~~~ = \int_0^2 \cos(x^2) y \bigg|_{y=0}^{y=x/2} \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^2 x \cos(x^2) \, dx

Substitute u=x^2 and du=2x\,dx.

\displaystyle \frac12 \int_0^2 x \cos(x^2) \, dx = \frac14 \int_0^4 \cos(u) \, du = \frac14 \sin(u) \bigg|_{u=0}^{u=4} = \boxed{\frac{\sin(4)}4}

4 0
1 year ago
14. Triangle QRS is shown below.
kifflom [539]
Ummm you tell me lol
4 0
3 years ago
Read 2 more answers
Imagine that you are standing at the top of a cliff that is 1,500 feet above sea level. You see ship A, and your eyes make an an
balandron [24]
Distance of A from cliff = 1500·arctan(30°) ≅ 723.5 ft

distance of B from cliff = 723.5+1000√3 ≅ 2455.6 ft
tanθ = 2455.6/1500 = 1.637
θ = arctan(1.637) ≅ 58.6°
angle of depression = 90-θ ≅ 30°
6 0
3 years ago
I need HELPPPP I'll mark you the brainliest!
maksim [4K]

B, x = 2

Step-by-step explanation:

Given the vertices of the image, and preimage of this right isosceles triangle, we can find the line of reflection by definitively understanding how reflections work. Given the preimage contains the points A(-1,1), B(1,-1), and C(-3,-1). And that the image contains the points A'(5,1), B'(3,-1), C'(7,-1). We can differentiate the corresponding points and apply them to the rules of a reflection. if figure Z is reflected over x = n,

than Z'(x,y) = Z(-x+2n,y). Logically, you can see that this pattern resembles all three coordinates for the transformation. i.e A'(5,1) = A(--1+2n,1) ; (1+2n,1) = (5,1) ; 1 + 2n = 5, 2n = 4, n = 2

we can prove this by using another point:

B'(3,-1) = (-1+2n,-1) = (-1 + 4, -1) = (3,-1)

Hopefully you understand,

<u>Pls mark brainliest this took me a very long time.</u>

3 0
3 years ago
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