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3 years ago

Given the reaction:

Chemistry

1 answer:

Lady bird [3.3K]3 years ago

8 0

Answer:

d) increase, producing a increase in the reaction rate

Explanation:

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Which of the following most likely happens during a physical change?

Svetlanka [38]

Answer:

A. New atoms are introduced in the molecules of the substance.

Explanation:

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4 0

3 years ago

Read 2 more answers

A 6.35 l sample of carbon monoxide is collected at 55.0◦c and 0.892 atm. What volume will the gas occupy at 1.05 atm and 59.0◦c?

Sonja [21]

Answer : The final volume of gas will be, 5.46 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.892 atm

$P_2$ = final pressure of gas = 1.05 atm

$V_1$ = initial volume of gas = 6.35 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $55.0^oC=273+55.0=328K$

$T_2$ = final temperature of gas = $59.0^oC=273+59.0=332K$

Now put all the given values in the above equation, we get:

$\frac{0.892atm\times 6.35L}{328K}=\frac{1.05atm\times V_2}{332K}$

$V_2=5.46L$

Thus, the final volume of gas will be, 5.46 L

7 0

3 years ago

What does an electromagnetic spectrum refer to?

Juliette [100K]

The entire distribution of electromagnetic radiation according to frequency or wavelength

7 0

3 years ago

A 100g of sample of a compound is combusted in excess oxygen and the products are 2.492g of CO2 and 0.6495 of H2O. Determine the

ruslelena [56]

The empirical formula : C₁₁O₁₄O₃

<h3>Further explanation</h3>

The assumption of the compound consists of C, H, and O

mass of C in CO₂ =

$\tt \dfrac{12}{44}\times 2.492=0.680~g$

mass of H in H₂O =

$\tt \dfrac{2.1}{18}\times 0.6495=0.072~g$

mass of O :

mass sample-(mass C + mass H)

$\tt 1-(0.68+0.072)=0.248`g$

mol of C :

$\tt \dfrac{0.68}{12}=0.056$

mol of H :

$\tt \dfrac{0.072}{1}=0.072$

mol of O :

$\tt \dfrac{0.248}{16}=0.0155$

divide by 0.0155(the lowest ratio)

C : H : O ⇒

$\tt \dfrac{0.056}{0.0155}\div \dfrac{0.072}{0.0155}\div \dfrac{0.0155}{0.0155}=3.6\div 4.6\div 1\\\\\dfrac{11}{3}\div \dfrac{14}{3}\div \dfrac{3}{3}=11:14:3$

3 0

3 years ago

An automobile gasoline tank holds 23 kg of gasoline. When the gasoline burns, 86 kg of oxygen is consumed, and carbon dioxide an

ira [324]

Question:

What is the total combined mass of carbon dioxide and water that is produced?

Answer:

Explanation:

When 23 kg of gasoline burns by consuming 86 kg oxygen, they produce carbon dioxide and water. To find the total combined mass of carbon dioxide and water, we will use mass conversation law.

According to mass conversation law, the mass of the product is equal to the mass of reagent.

Mass of reagent = Mass of product

In this reaction,

Gasoline + O2 → CO2 + H2O

23 kg + 86 kg → ?

23 kg + 86 kg = 109 kg

Combined mass of carbon dioxide and water will be 109 kg.

4 0

3 years ago