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motikmotik
3 years ago
12

Please, What is the mass of oxygen in 72.0g of water? [ H= 1.0; O = 16.0]

Chemistry
1 answer:
yarga [219]3 years ago
5 0
Convert 72g of water into moles of water using molecular weights.

So water is H2O so add up those molecular weights (H=1 and O=16)

2(1)+(16) = 18 g/mol

Then convert so 72g / (18 g/mol) = 4 mol

Now you can convert mol of water to mol of oxygen. So 4 mol of water is 4 mol of oxygen. Then use oxygen molecular weight to find grams again.

4 mol oxygen * 16 g/mol = 64g of oxygen

If we were doing hydrogen instead of oxygen there would be 8 mol hydrogen in 4 mol of water (2 H’s in every H2O molecule) and since we have 74 grams and oxygen is 64 grams, Hydrogen should be 8 grams. Math to check below

8 mol hydrogen * 1 g/mol = 8g of hydrogen

It all adds to 72 so we are correct.
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4 years ago
The solubility of solid W in water is: 1.72 g/100 mL at 0°C, 21.3/100 mL at 100°C. a) How many mL of boiling water are required
grandymaker [24]

Answer:

a) Mass of solid W crystallized out 0°C is 141.564 g

b) 91.92% is the percent recovery.

Explanation:

The solubility of solid W in water at 100°C = 21.3 g/100 mL

Volume of water at 100C required to dissolve 154.0 g of W: x

\frac{154.0 g}{x}=\frac{21.3 g}{100 mL}

x=\frac{154.0 g\times 100 mL}{21.3 g}=723.0 mL

723.0 mL of water will dissolve 154.0 grams of solid W.

The solubility of solid W in water at 0°C = 1.72 g/100 mL

Mass of W soluble in 723.00 mL of water at  0°C = m

\frac{m}{723.0 mL}=\frac{1.72 g}{100 mL}

m=\frac{1.72 g\times 723.0 mL}{100 mL}=12.436 g

a) Mass of solid W crystallized out 0°C : 154.0 g- 12.436 g=141.564 g

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\frac{141.564 g}{154.0 g}\times 100=91.92\%

91.92% is the percent recovery.

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3 years ago
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