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3 years ago

Explain why alkanes can be described as hydrocarbons.

Chemistry

1 answer:

worty [1.4K]3 years ago

5 0

Answer:

<h3>The International Union of Pure and Applied Chemistry (IUPAC) defines alkanes as "acyclic branched or unbranched hydrocarbons having the general formula CnH2n+2, and therefore consisting entirely of hydrogen atoms and saturated carbon atoms". ... The number of carbon atoms may be considered as the size of the alkane.</h3>

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When 220 mL of 1.50x10^-4 M hydrochloric acid is added to 135 mL of 1.75x10^-4 M Mg(OH)2, the resulting solution will be________

siniylev [52]

Answer:

Basic

Explanation:

Considering

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

So,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

For hydrochloric acid :

Molarity = $1.50\times 10^{-4}$ M

Volume = 220 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 220×10⁻³ L

$Moles =1.50\times 10^{-4} \times {220\times 10^{-3}}\ moles$

Moles of hydrochloric acid = 0.000033 moles

For $Mg(OH)_2$ :

Molarity = $1.75\times 10^{-4}$ M

Volume = 135 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 135×10⁻³ L

$Moles =1.75\times 10^{-4} \times {135\times 10^{-3}}\ moles$

Moles of $Mg(OH)_2$ = 0.000024 moles

According to the given reaction:

$Mg(OH)_2_{(aq)}+2HCl_{(aq)}\rightarrow MgCl_2_{(s)}+2H_2O_{(aq)}$

1 mole of $Mg(OH)_2$ reacts with 2 moles of HCl

Also,

0.000024 mole of $Mg(OH)_2$ reacts with 2*0.000024 moles of HCl

Moles of HCl = 0.000048 moles

Available moles of HCl = 0.000033 moles

Limiting reagent is the one which is present in small amount. Thus, HCl is limiting reagent.

Thus, HCL will be consumed completely and $Mg(OH)_2$ will be left over. Thus, the resulting solution will be basic.

4 0

4 years ago

A mixture of helium, neon, and xenon gases is made with the same mass of each gas. Which (if any) gas will have the highest part

Darya [45]

Answer:

Xe will have the highest partial pressure

Explanation:

Using Dalton's law of partial pressures for ideal gases

p=P*x

where

p= partial pressure , P= total pressure and x = mole fraction = n / ∑n

since the number of moles is related with mass through

n= m/M

where

m= mass and M= molecular weight

then if m is the same for all the gases

x = m*M/ ∑ (m*M) = m*M/ m∑ M = M/∑ M

thus

p=P*x = P*M/ ∑ M

for the 3 gases

p₁=P*x₁ = P*M₁/ (M₁+M₂+M₃)

p₂=P*x₃ = P*M₂/ (M₁+M₂+M₃)

p₂=P*x₃ = P*M₃/ (M₁+M₂+M₃)

then for gasses under the same pressure (P=constant) and same mass (m=constant) , p is higher when the molecular weight is higher . Therefore Xe will have the highest partial pressure

5 0

4 years ago

Read 2 more answers

How many moles FeBr3 are required<br> to generate 275 g NaBr?<br><br> 2FeBr3 + 3Na₂S → Fe₂S3 +6NaBr

slega [8]

Answer:

0.893mol

Explanation:

n = m ÷ M

= 275 ÷ (23 + 80)

= 2.67 mol

* now use the Mol ratio *

NaBr : FeBr3

6 : 2

2.67 : x

5.67 = 6x

n( FeBr3 ) = 0.893 mol

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2 years ago

Which statement correctly describes protons and neutrons?

a_sh-v [17]

Answer:

Explanation:

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maksim [4K]

Answer:

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