The answer for this problem is 70
Answer:
(3,-2)
Step-by-step explanation:
Given equations of line
3x-2y=13
2y+x+1=0
=> x = -1 -2y
Point of intersection will coordinates where both equation have same value of (x,y)
top get that we have to solve the both equations by using method of substitution of simultaneous equation.
using this value of x in 3x-2y=13, we have
3(-1-2y) -2y = 13
=> -3 -6y-2y = 13
=> -8y = 13+3 = 16
=> y = 16/-8 = -2
x = -1 - 2y = -1 -2(-2) = -1+4= 3
Thus, point of intersection of line is (3,-2)
First plug in 2 for r like so:
-9(2) - 7
To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)
REMEMBER: IF NOT APPLICABLE TO THE EQUATION YOU MAY SKIP THAT STEP IN PEMDAS .
First we have multiplication:
-9(2) - 7
-9(2) = -18 <<< When multiplying a negative and positive number together you will multiply normally and the answer will have a negative sign
-18 - 7
Now for the subtraction:
-18 - 7 <<< When subtracting with a negative number you will do something called "Same-Add-Opposite." This means that you will keep the first number in the expression (in this case that is -18) the same. Then turn the subtraction sign into an addition sign. Finally you will take the "opposite" sign of the second number. When I say "opposite sign" I mean that if this number is positive it will become negative. If it was negative it will become positive.
Here is your expression after applying same - add - opposite:
-18 + (-7)
-25
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer: 4(3y−1)
Step-by-step explanation:
Are you working with angles or substitution? If so what are the answer choices or N/A