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Ugo [173]
3 years ago
12

Find the measure of angle 1

Mathematics
1 answer:
kolbaska11 [484]3 years ago
3 0

Answer:

44°

Step-by-step explanation:

8x - 4 = 6x + 8 (This is because they are corresponding angles)

8x - 6x = 8 + 4

2x = 12

x = 12 ÷ 2

x = 6

6x + 8 = angle 1 (Vertically opposite angles are equal)

Substitute the value of x in the equation '6x +8' to get the size of the angle.

6 × 6 + 8

36 + 8 = 44°

Angle 1  =  44°

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I need help plzzzz!!!!!! find the area
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Answer:

3

Step-by-step explanation:

Area = 1/4 * √(5(5+2√5)) * a^2

Area ≈387.11

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7 0
3 years ago
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During 2021, equipment was sold for $470000. The equipment cost $782000 and had a book value of $439000. Accumulated Depreciatio
algol [13]

Answer:

$149,000

Step-by-step explanation:

Subtract acc depreciation for 2020 from acc deprecitation in 2021 and it gives you the depreciation expense solely for 2021.

4 0
3 years ago
What are the minimum and maximum distances that Morgan’s dog may be from the house? (Algebra ll) *URGENT*
Mashcka [7]

Given:

The minimum and maximum distance that the dog may be from the house can be found by using the equation:

|x-500|=8

To find:

The minimum and maximum distance that the dog may be from the house.

Solution:

We have,

|x-500|=8

It can be written as:

x-500=\pm 8

Adding 500 on both sides, we get

x=500\pm 8

Now,

x=500+8 and x=500-8

x=508 and x=492

The minimum distance is 492 meters and the maximum distance is 508 meters.

Therefore, the correct option is C.

6 0
3 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
Help please! Figure JKLM is a parallelogram. The measures of line segments MT and TK are shown. What is the value of MT? A.) 7 B
Zinaida [17]

Hey there! :)

Answer:

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8(7) + 18 = 74 units.

3 0
3 years ago
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