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3 years ago

Arithmetic of functions

Mathematics

1 answer:

Rzqust [24]3 years ago

5 0

Its B.

If $f(x)=4x+1$ and $g(x)=x^2-5$ then, $(\frac{g}{f})(x)=\frac{x^2-5}{4x+1}$ and $x\neq-\frac{1}{4}$ because if x were $-\frac{1}{4}$ then you would have division by 0.

Hope this helps.

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