Question

Arithmetic of functions

Answer 1

Its B.

If $f(x)=4x+1$ and $g(x)=x^2-5$ then, $(\frac{g}{f})(x)=\frac{x^2-5}{4x+1}$ and $x\neq-\frac{1}{4}$ because if x were $-\frac{1}{4}$ then you would have division by 0.

Hope this helps.