Answer: c I think if I’m wrong report my comment
Answer:
![\sqrt[n]{x^a}=x^{a/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ea%7D%3Dx%5E%7Ba%2Fn%7D)
Step-by-step explanation:
While the "law"
![\sqrt[n]{x^n}=x](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D%3Dx)
may seem more applicable, and may seem to be a special case of the law shown in the answer above, it is not true in general. For example, ...
The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
Read more about quadratic function at
brainly.com/question/25841119
#SPJ1
Answer:
no it is not
Step-by-step explanation:
it would be 54
