The side lengths of the pool 10 ft and 45 ft.
<u>SOLUTION:
</u>
Given, a rectangle swimming pool is 8 feet deep.
One side of the pool is 4.5 times longer than the other.
Let the length of pool be n feet, the width will be 4.5n feet
The amount of water needed for the swimming pool is 3600 cubic ft
We have to find the dimensions of the pool. Now, we know that,
On taking square root on both sides we get,
So, the width will be 
X+y=2 (label equation one)
x-y=4 (label equation two)
y=-x+2 (equation one rearranged, label this equation equation three)
sub 3 into 2
x-(-x+2)=4
x+x-2=4
2x-2=4
2x=6
x=3
sub x=3 into equation one
3+y=2
y=-1
therefore x=3 and y=-1
Answer:
The correct answer is D because they are unknown
Step-by-step explanation:
Answer:
Area = (36π - 12πx + x²π) mm²
Step-by-step explanation:
Given that,
radius of lense = 6mm
Length from outer layer of pupil to lense = x mm
Radius of pupil = 6 - x mm
<h3>
Formula to calculate area of pupil</h3><h3>
Area = π r²</h3>
<em> where r is radius of pupil</em>
Area = π (6 -x)²
Area = π (6² -2(6)(x) + x²)
Area = π (36 -12x +x²)
Area = (36π - 12πx + x²π) mm²
So, the polynomial in standard form that represent the area of pupil in terms of π = (36π - 12πx + x²π) mm²
