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Alex
3 years ago
9

Options are: X=2, y=3 X=3, y=2 X= -2, y=3 X=4, y=8

Mathematics
2 answers:
enot [183]3 years ago
7 0

Answer:

x = 4, y = 8

Step-by-step explanation:

For the triangles to be congruent by the HL theorem

Then the hypotenuse and legs must be congruent , that is

x + 1 = y - 3 → (1)

2x - 5 = y - 5 → (2)

Subtract (1) from (2) term by term to eliminate y

2x - x + (- 5) - 1 = y - y + (- 5) - (- 3) , that is

x - 6 = - 2 ( add 6 to both sides )

x = 4

Substitute x = 4 into either of the 2 equations and solve for y

Substituting into (1)

4 + 1 = y - 3

5 = y - 3 ( add 3 to both sides )

8 = y

trapecia [35]3 years ago
5 0

Step-by-step explanation:

2x - 5 = y - 5

2x = y

x = y/2

y - 3 = x + 1

Substitute the value of x here,

y - 3 = \rm{\dfrac{y}{2} + 1}

y - 3 = \rm{\dfrac{y + 2}{2}}

2y - 6 = y + 2

y = 8

Now, x = 8/2

x = 4

So, go for D part, it is the correct answer.

Good Night/Day !

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A popular soft drink is sold in 2-liter (2000 milliliter) bottles. Because of variation in the filling process, bottles have a m
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Answer:

a) 0.27% probability that the mean is less than 1995 milliliters.

b) 2002.3 milliliters or more will occur only 10% of the time for the sample of 100 bottles.

Step-by-step explanation:

To solve this problem, it is important to understand the normal probability distribution and the central limit theorem

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2000, \sigma = 18

A) If the manufacturer samples 100 bottles, what is the probability that the mean is less than 1995 milliliters?

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Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

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Z = -2.78 has a pvalue of 0.0027

So 0.27% probability that the mean is less than 1995 milliliters.

B) What mean overfill or more will occur only 10% of the time for the sample of 100 bottles?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9.

So it is X when Z = 1.28

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X = 2002.3

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