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Llana [10]
2 years ago
12

When multiplying 1,729 times 308, Clayton got a product of 53,253. Without

Mathematics
1 answer:
fomenos2 years ago
5 0

Answer:

Well, let's try and estimate it! Let's say.....1,700 times 300. or even to simplify it a bit more 2000 times 300.

Step-by-step explanation:

First, 1,700 times 300 is 510,000. Since you already know that you can figure out that it's already not true.

2000 times 300 is 600000. So that also comes into context.

Hope this helps!

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Lorenzo went to the store with 20$. He bought some cans of soup for 2$ each and a gallon of milk for 3$. He had 1$ left over.
Dominik [7]
2s + 3 = 19
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s = 8
He can buy 8 cans of soup.
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3 years ago
The average price (in dollars) to rent a studio in a certain city can be approximated by the equation p=28.2t+644 where t is the
egoroff_w [7]

p = 28.2t + 644\\\\p-644 = 28.2t\\\\\frac{p-644}{28.2} = \frac{28.2t}{28.2}\\  \\t = \frac{p-644}{28.2}

t = \frac{1320.80-644}{28.2} \\\\t = 24

It will take 24 years.

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3 years ago
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8 0
3 years ago
Read 2 more answers
90. The number of daily evening newspapers in the United States has decreased by 46.5% to
aleksandr82 [10.1K]

Answer:

700

Step-by-step explanation:

Given:

Daily evening newspapers in 2015 = 389

Percentage decrease from 2000 to 2015 = 46.5%

To find:

Number of newspapers in 2000 = ?

Solution:

Let the number of newspapers in 2000 = x

When 46.5% of the total newspapers in 2000 (x) is subtracted from the total  newspapers in 2000 (x), it will be equal to the number of newspapers in 2015.

Making the equation as per the given statement:

x-x\times 46.5\%=389\\\Rightarrow \dfrac{100x-46.5x}{100}=389\\\Rightarrow 53.5x=38900\\\Rightarrow x\approx \bold{727}

Therefore, the answer is:

There were <em>727 </em>newspapers in 2000.

7 0
3 years ago
F(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2-4%7D" id="TexFormula1" title="\sqrt{x^2-4}" alt="\sqrt{x^2-4}" align="abs
hammer [34]

Solve for <em>x</em> when √(<em>x</em> ² - 4) = 1 :

√(<em>x</em> ² - 4) = 1

<em>x</em> ² - 4 = 1

<em>x</em> ² = 5

<em>x</em> = ±√5

We're looking at <em>x </em>≤ 0, so we take the negative square root, <em>x</em> = -√5.

This means <em>f</em> (-√5) = 1, or in terms of the inverse of <em>f</em>, we have <em>f</em> ⁻¹(1) = -√5.

Now apply the inverse function theorem:

If <em>f(a)</em> = <em>b</em>, then  (<em>f</em> ⁻¹)'(<em>b</em>) = 1 / <em>f '(a)</em>.

We have

<em>f(x)</em> = √(<em>x</em> ² - 4)   →   <em>f '(x)</em> = <em>x</em> / √(<em>x</em> ² - 4)

So if <em>a</em> = -√5 and <em>b</em> = 1, we get

(<em>f</em> ⁻¹)'(1) = 1 / <em>f '</em> (-√5)

(<em>f</em> ⁻¹)'(1) = √((-√5)² - 4) / (-√5) = -1/√5

The sign must be negative; see the attached plot, and take note of the negatively-sloped tangent line to the inverse of <em>f</em> at <em>x</em> = 1.

3 0
3 years ago
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