It can go into the group integers, as well as rational numbers.
Hope this helps you! Happy thanksgiving, here's a turkey!
<h3>
<u>Explanation</u></h3>
The vertex of Parabola is the maximum/minimum point depending on the value of a.
<u>h-value</u>
<u>k-value</u>
The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.
This is Calculus method. We simply differentiate the function then substitute y' = 0.
Substitute f'(x) = 0
Substitute x = -5/2 in the original equation.
<h3>
<u>Answer</u><u /></h3>
<u>
</u>
Answer:
gyuggbgzsZdxfghuiguyftdrtffyurtyryjjb
Step-by-step explanation:
Answer:
Step-by-step explanation:
The graph passes through the origin. It could either open up or open down. The quadratic has two zeros, both at (0, 0).
Hi there!
The question here is asking us to multiply two functions together - j(x) and k(x). First, we need to determine the expressions for j(x) and k(x). Since this is given, we can move straight onto multiplying the two functions together, which will give us our answer.
j(x) × k(x)
Substitute expressions -
(x⁴ - 81)(x + 3)
Simplify -
(x⁴ - 81)(x + 3)
x⁵ + 3x⁴ - 81x - 243
Therefore, the answer is x⁵ + 3x⁴ - 81x - 243. Hope this helped!
