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3 years ago

Solve the equation x2 = 80. X =

Mathematics

1 answer:

Tasya [4]3 years ago

8 0

Answer:

x=40

Step-by-step explanation:

hope i helped

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The Choi family bought 6 bags of cookies. Each bag had 15 cookies. They have since eaten 28 of the cookies. How many cookies do

Norma-Jean [14]

Answer:

They have 62 cookies left

Step-by-step explanation:

6 X 15 = 90

90 - 28 = 62

3 0

2 years ago

clint has 6 apple muffins, 2 corn muffins, and 4 bran muffins what fraction of muffins are bran weite the fraction in simplest f

Feliz [49]

Answer:

$\frac{1}{3}$

Step-by-step explanation:

The fraction of bran muffins is expressed as bran muffins over total muffins.

Total muffins = 6 + 2 + 4 = 12 and bran muffins = 4, thus

fraction = $\frac{4}{12}$ ← divide ( cancel ) each value by 4 )

fraction = $\frac{1}{3}$ ← in simplest form

6 0

2 years ago

Read 2 more answers

How many triangles can be constructed with angles measuring 110°, 50°, and 20°?

lutik1710 [3]

The answer would be B) more than one hope this helped you!

8 0

3 years ago

Read 2 more answers

How many times does 61 go into 340

TiliK225 [7]

I think maybe about 5 times

4 0

2 years ago

Read 2 more answers

M1 Matrix is:

harkovskaia [24]

Answer:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

Step-by-step explanation:

Given matrix $M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)$

The Inverse of a 2X2 matrix

$A=\left(\begin{array}{ccc}a&b\\c&d\end{array}\right)$

can be found using the following:

$A^{-1}=\dfrac{1}{ad-bc} \left(\begin{array}{ccc}d&-b\\-c&a\end{array}\right)$

Therefore:

$M^{-1}=\dfrac{1}{(5*-5)-(3*-8)} \left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=-1\left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)$

Next, we find the product $M^{-1}M$

$M^{-1}M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\\=\left(\begin{array}{ccc}-5*-5+3*-8&-5*3+3*5\\-8*-5+5*-8&-8*3+5*5\end{array}\right)\\=\left(\begin{array}{ccc}1&0\\0&1\end{array}\right)$

Therefore:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

NOTE: The multiplication of a matrix and its inverse always gives the identity matrix as seen above,

7 0

2 years ago