All categories

2 years ago

You have 90.43 in your bank account and you make a deposite. Your account will:

Mathematics

2 answers:

quester [9]2 years ago

8 0

Answer:

be adding more money

Step-by-step explanation:

deposit means to add withdraw means to take out

marin [14]2 years ago

7 0

Answer:

increase

Step-by-step explanation:

You might be interested in

Identify the greatest common factor. 20x^5 - 8x^4 +12x^2

Ugo [173]

4x^2 is the greatest commonly factor for these exponents.

Hope this helps you! :)

5 0

3 years ago

Solve for p if 2|p| = 4

ehidna [41]

2p = 4
p = 2

-2p = 4
p = -2

answer p = -2 and p =2

3 0

3 years ago

Read 2 more answers

Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y

professor190 [17]

Answer:

Required total charge is $256\pi$ coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

$x^2=y^2\leq 16$ so that the charge density at (x,y) is,

$\rho (x,y)=2x+2y+2x^2+2y^2$

To find total charge on the disk let Q be the total charge and $x=r\cos\theta,y=r\sin\theta$ so that,

$Q={\int\int}_Q\rho(x,y) dA$ where A is the surface of disk.

$=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA$

$=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta$

$=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta$

$=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta$

$=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta$

$=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi$

$=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi$

$=256\pi$

Hence total charge is $256\pi$ coulombs per square meter.

3 0

3 years ago

Let f(x) = x2 − 16. Find f−1(x)

Yanka [14]

Answer:

$f^{-1}(x)=\pm\sqrt{x+16}$

Step-by-step explanation:

$f(x)=x^2-16$

To find the inverse of this function, temporarily the f(x) with a y (or whatever else you want) and then solve for the x.

$y=x^2-16\\y+16=x^2\\x=\pm\sqrt{y+16}$

Now, you can swap the variables again and write the function.

$f^{-1}(x)=\pm\sqrt{x+16}$

3 0

2 years ago

How to simplify -3 (4×-5y-5×)

VMariaS [17]

Distribute -3 to the rest of the numbers by multiplying them together. That’s all you need to do you don’t have to solve

6 0

3 years ago

Read 2 more answers