This response is based upon your having had some background in calculus. "dx" is not introduced before that.
Take a look at the sample function y = f(x) = x^2 + 9. Here x is the independent variable; the dependent variable y changes with x.
Now, for a big jump: we consider finding the area under a curve (graph) between x = a and x = b. We subdivide that interval [a,b] into n vertical slices of area. Each of those slices has its own area: f(x)*dx, where dx represents the width of such subarea. f(x)*dx is the actual subarea. To find the total area under the curve f(x) between x= a and x = b, we add up all of these individual subareas between x = a and x = b. Note that the subinterval width is
b-a
dx = ---------- , and that dx becomes smaller and smaller as the number of
n subintervals increases.
Once again, this all makes sense only if you've begun calculus (particularly integral calculus). Do not try to relate it to earlier math courses.
3 buckets covers 90m x 80cm = 3 buckets for 90x0.8 = 3 for 72
x buckets covers 200m x 120cm = x buckets for 200x1.2 = x for 240
3/72 = x/240
720 = 72x
x =10 buckets of paint to cover 200mx120cm fence
Answer:
x = 1091.63315843
<span>
Setting Up:
7 = ln ( x + 5 )
ln translates to "log" with an "e" as the base or subscript ( a small "e" at the bottom right of the "g" in log).
You take the base of the log and put it to the power of "7" ( "7" is the natural log of ( x + 5 ) in this problem ).
The value of which the logarithm is calculated is set equal to the base of the logarithm to the power of the calculated logarithm of the value.
e^7 = x + 5
Solving</span>:
e = 2.71828182846
Natural logarithms are logarithms to the base of the constant 'e'.
e^7 = x + 5 ( simplify e^7 )
<span>1096.63315843 = x + 5
</span>
Subtract 5 from each side.
1091.63315843 = x
Answer:
option 4
Step-by-step explanation:
y = 4x-3
y = 4(1)-3
y = 1
y = 4(3)-3
y = 9
y = 4(5)-3
y = 17
y = 4(7)-3
y = 25
Rectangle A’B’C’D’ has a scale factor of 2 because it is two times bigger then the original rectangle ABCD after the dilation.