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kiruha [24]
3 years ago
14

Suppose radius CA is a 12 meters long. What is the diameter of the circle

Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

24m

Step-by-step explanation:

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Simplify 9 x 5/9<br> in 4 mins
Triss [41]

Answer:

5

Step-by-step explanation:

9 x 5/9

9/1 * 5/9

Rewriting

9/9 * 5/1

1 * 5/1

5

6 0
3 years ago
Read 2 more answers
For what value of the domain {–3, –1, 0, 2, 5} does f(x) = g(x) When f(x) = 3x – 4 and g(x) = x2 – 2
zavuch27 [327]
F(x) = g(x)
3(2) - 4 = (2)² - 2
6 - 4 = 4 - 2
2 = 2
I just substituted all the values in the domain to see which one would work. That's not really the quickest way but that's the only way I know

7 0
3 years ago
Find the value of the expression. 4 + 8 ÷ 2 – 1 <br> a.19<br> b.7<br> c.12<br> d.5
astraxan [27]

First Division, next Addition and Subtraction (left-to-right)

4 + 8 : 2 - 1 = 4 + 4 - 1 = 8 - 1 = 7

<h3>Answer: b. 7</h3>
6 0
3 years ago
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

3 0
3 years ago
I will give u 100 points if u can answer this quition pls it is hard for me John has three pieces of rope. One piece was 31 cm l
serious [3.7K]

Answer:

Add 0.31 + 0.33 + 0.45;

Step-by-step explanation:

Hope I got it right! If not i'm sorry.

7 0
3 years ago
Read 2 more answers
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