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Anarel [89]
3 years ago
14

Subtract - 7x2 + 1 from – 2x2 - 4x.

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

11-4x

Step-by-step explanation:

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valerie has 10 Video games. 7 of her video games are racing games. what is valerie's racing games written as a decimal?​
svet-max [94.6K]

Answer:

7/10.

Step-by-step explanation:

If theres a total of 10 games and 7 out of the 10 are racing games, it means that 7/10 of the games are racing games.

6 0
3 years ago
Read 2 more answers
-16t squared + 16t + 480 t=time after jumping in seconds h=height in feet How many seconds did did it take her to hit the water
Agata [3.3K]
That is height
h=16t^2+16t+480
when h=0 is when it hits the water

0=16t^2+16t+480
undistribbute 16 for ease
0=16(t^2+t+30)
16*0=0 so assume
t^2+t+30=0
factor
(t+6)(t-5)=0
set to zero

t+6=0
minus 6
t=-6
false, since you cannot have negative time

t-5=0
add 5
t=5

at t=5 she hits the water


5 seconds
4 0
3 years ago
I need help what is 1/3x-3?​
lilavasa [31]

Answer:

\frac{1}{3}x-3=\frac{x}{3}-3

Step-by-step explanation:

\frac{1}{3}x-3\\\\\frac{1}{3}x = \frac{x}{3}  \\\\Find\:L.C.M.\\\\=\frac{x}{3}-3

8 0
3 years ago
Which units should she use to report the distance from the earth to the moon?
Anvisha [2.4K]
Well,

The distance from the earth to the moon, FYI, is over 200,000 miles.  That is a LONG distance.  We are trying to find a reasonable unit of measurement.

What do we mean by "reasonable?"  We mean that that unit should be able to express the distance as a number that is not huge or tiny.  In other words, we want it to be as close as possible to 1.

mm, or millimeters, is a tiny unit.  It is not reasonable.

cm, or centimeters, is also a tiny unit.  It also is not reasonable.

m, or meters, is also a relatively small unit.  It also is not reasonable.

km, or kilometers, is the largest of the four.  In km, the distance from the earth to the moon is about 363,000 km.  That's not too bad.

However, if these weren't the only options, I would choose Mm, or megameters, which would put the distance at 363 Mm.

The correct option is D.
7 0
3 years ago
Suppose two random variables, X and Y are independent, which statement is false? a) P(X∣Y)=P(X) b) P(X∪Y)=P(X)+P(Y) c) P(X∩Y)=P(
Svetlanka [38]

B is false, since by the inclusion/exclusion principle,

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)

By independence, we have P(X\cap Y)=P(X)P(Y), which is zero if either of P(X) or P(Y) is 0, which isn't guaranteed.

5 0
3 years ago
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