The first thing to do is find the rectangular warehouse area. We have then: A = (12) * (18) = 216 A = 216 m ^ 2 We now look for the area of each acoustic tile square: A '= (1) ^ 2 = 1 A '= 1 m ^ 2 We look for acoustic tile squares number: N = (A) / (A ') N = (216) / (1) N = 216 Finally we look for the total weight: W = (1/4) * (216) W = 54 Kg Answer: The total weight of the tile required to cover the ceiling is: W = 54 Kg