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2 years ago

Are these ratios equivalent? 2:4 and 6:16

Mathematics

2 answers:

Grace [21]2 years ago

4 0

Answer:

Step-by-step explanation:

2:4 is 1:2, 6:16 is not one half

adelina 88 [10]2 years ago

3 0

Answer:

Step-by-step explanation:

4/2=2

16/6=2.666666667

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The product of 6<br> and the sum of five<br> and a number

Vaselesa [24]

Answer:

6 * (5 + n)

Explanation:

Sum = addition

Difference = subtraction

Product = multiplication

Quotient = division

6 0

1 year ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

Kelso is in charge of a bake sale. On each table, t, there will be a platter of 24 cookies and 2 bowls of brownies with b browni

Phantasy [73]

24*7 = 168
(2*12)*7=168
168*2=336

336 Total sweets

8 0

3 years ago

Sin tita= 0.6892.find the value Of tita correct to two decimal places<br><br>

Anvisha [2.4K]

Answer:

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

Considering $\theta \in (0, 2\pi]$

$\theta \approx 2.38$

$\theta \approx 0.76$

Step-by-step explanation:

$\sin(\theta)=0.6892$

We have:

$\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}$

Therefore,

$\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}$

$\theta = \pi -\arcsin (0.6892)+2\pi n, \quad n\in \mathbb{Z}$

---------------------------------

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

4 0

3 years ago

X(z + 3) + 1 + 3 − y; use x = 6, y = −5, and z = 2

Stels [109]

Answer: 39

Step-by-step explanation:

x(z+3)+1+3-y

plug in the values given for each variable

6(2+3)+1+3-(-5)

use pemdas to solve

6(5)+1+3+5

30+1+3+5

31+8

4 0

3 years ago

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