Answer:
A sample size of 79 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?
A sample size of n is needed.
n is found when M = 0.09. So






Rounding up to the nearest whole number.
A sample size of 79 is needed.
Its is greater, your welcome xoxo savi eden
5+7+11=23
3+11+53=67
3+11+61=71
are some examples
the Highest common factor of 130,260,390 = 130
130 = 2⋅5⋅13
260 = 2⋅2⋅5⋅13
390 = 2⋅3⋅5⋅13
Common multipliers (130; 260; 390): 2, 5, 13
Now to find the highest Common factor you need to multiply the common factors
Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130