If a number is raised to a power of 2, it is <br> (a) cubed <br> (b) powered<br> (c) squared

Y = 4x - 2<br> y = x + 3

mihalych1998 [28]

Answer:

Step-by-step explanation:

x = 1

(x^2-4x+3=0 or sin(x)=1)

x = 1

( x^2-4x+3=0 or sin(x)=1)

3 0

3 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago

Identify the matrix transformation of ΔKLM, which has coordinates K(−2, 3),L(−4, −2), and M(−3, 0), for reflection across the x-

mafiozo [28]

Lol Kinda hard try again

3 0

2 years ago

The franklins have a home loan with an interest rate of 4 1/4%. write the percent as a fraction in simplest form.

alex41 [277]

4 1/4 % =
4.25% =
0.0425 =
425/10,000 =
17/400 <==

8 0

3 years ago

Read 2 more answers

Divide use partial quotients 36 divided by 540

Blizzard [7]

Answer and explanation;

= 1/15 is the answer get when 36 is divided by 540 .

We can use the partial quotients to divide 540 by 36 then we get the reciprocal of the answer;

540 ÷ 36

We can take 360 ÷ 36 = 10

Then the remainder is ; 540 -360 = 180

But ; 180 ÷36 = 5

Then we get the sum of the quotients which is 10 +5 = 15

Thus; 540 ÷ 36 = 15

However; the question was 36 ÷ 540 , so we get the reciprocal of 15;

= 36 ÷ 540 = 1/15

8 0

3 years ago

Read 2 more answers

If a number is raised to a power of 2, it is (a) cubed (b) powered (c) squared