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Dennis_Churaev [7]
3 years ago
14

Theo and Kade worked on a school project together. Theo worked on the project 3 fewer hours than Kade did. Altogether, they work

ed for a total of 27 hours. How many hours did they each work on the school project?
Theo worked on the project for
hours.
Kade worked on the project for
hours.
Mathematics
2 answers:
kow [346]3 years ago
6 0

Answer:Theo worked for 10.5 hours.

Kade worked for 16.5 hours

Step-by-step explanation:

grigory [225]3 years ago
3 0

Answer:

Theo worked on the project for 12 hours, and Kade worked on the project for 15 hours.

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Find the length of x. help please !
andreyandreev [35.5K]

Answer:

x = 10

Step-by-step explanation:

Use CPCTC (Corresponding parts of congruent triangles are congruent).

Set the ratios:

\frac{6.5}{5} = \frac{6.5 + 6.5}{x}

First, simplify. Combine like terms:

\frac{6.5}{5} = \frac{13}{x}

Next, cross multiply.

5 * x * \frac{6.5}{5}  = \frac{13}{x} * x * 5\\x * 6.5 = 13 * 5\\6.5x = 65\\

Isolate the variable, x. Divide 6.5 from both sides of the equation:

\frac{(6.5x)}{6.5} = \frac{(65)}{6.5} \\\\x = \frac{65}{6.5}\\x =  10

Check:

\frac{5}{6.5} = \frac{x}{13}

Plug in 10 for x (Your answer). Cross multiply, then simplify:

\frac{5}{6.5} = \frac{10}{13}

13 * 6.5 * \frac{5}{6.5} = \frac{10}{13} * 13 * 6.5

13 * 5 = 10 * 6.5

65 = 65 (True).

~

6 0
3 years ago
The angle \theta_1θ
enyata [817]

Answer:

sin\theta_1 = \dfrac{\sqrt{217}}{19}

Step-by-step explanation:

It is given that:

cos\theta_1 = -\dfrac{12}{19}

And we have to find the value of sin\theta_1 = ?

As per trigonometric identities, the relation between sin\theta\ and \ cos\theta can represented as:

sin^2\theta + cos^2\theta = 1

Putting \theta_1 in place of \theta Because we are given

sin^2\theta_1 + cos^2\theta_1 = 1

Putting value of cosine:

cos\theta_1 = -\dfrac{12}{19}

sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}

It is given that \theta_1 is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}

8 0
3 years ago
What is the product of (negative 6) (negative 7) (negative 1)?
Neporo4naja [7]

Answer:

-42

Step-by-step explanation:

negative * negative = positive

positive * negative = negative

negative * positive = negative

(-6)(-7)(-1) =

= 42(-1)

= -42

5 0
3 years ago
Can someone help me with this ?
KatRina [158]

Answer:

yes I can help you with this but I don't know it

8 0
2 years ago
in a batch of 280 water purifiers,12 were found to be defective. what is the probability that a water purifier chosen at random
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4.286%

Step-by-step explanation:

12/280=0.04286*100=4.286/100 or 4.286%

4 0
3 years ago
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