H(t) = -16t2 + 186t + 43
at the ground h = 0
hence; -16t2 + 186t + 43 = 0
solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 - 4ac)1/2)/2a
gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)
Answer:The answer has to be 9
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Step-by-step explanation: Because 2 plus 9 equals 11 and this is an addition problem
36 i guess ha please that not right
Answer:
All real values of x such that x ≥-3
Step-by-step explanation:
g(x) = sqrt(x+3)
A sqrt must be greater than or equal to zero
sqrt (x+3) ≥ 0
Square each side
x+3≥ 0
Subtract 3 from each side
x ≥-3
The restrictions on x are x ≥-3
That means the domain is x ≥-3
All real values of x such that x ≥-3
A= π r ²
Take half of the diameter for the radius, so the radius is 2m
A=π 2 ²
A= 12.57 m²
So, yes, you are correct
