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Zielflug [23.3K]
3 years ago
12

How do you add a decimal

Mathematics
2 answers:
fiasKO [112]3 years ago
7 0
When adding decimals always line them up 
for example:    5.23
                      +6.35
                       --------
                      11.58
see simple hope I helped

harkovskaia [24]3 years ago
4 0

Answer:

Ignore the decimal until its needed

Step-by-step explanation:

Adding decimals is easy. All you need to do is remove the decimals from your simple addition equation, and solve. Then, you need to add the decimal in the depending on the number 2nd place for example

12.00 + 13.00

remove the decimal

1200 + 1300 = 2500

add the decimal

12.00 + 13.00 = 25.00

This is also helpful with decimals that don't have any zeros for example:

12.32 + 45.62

remove the decimal

1232 + 4562 = 5794

add the decimal

12.32 + 45.62 = 57.94

Their are better and more efficient ways to add decimals but if you think on a lower level than others or like to think in a less complex way to help math work be less confusing, then, I would consider this way of adding decimals,

(Thanks)

(Hope this was helpful)

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A parabola is a mirror-symmetrical U-shape.

  • The equation of the parabola is \mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}
  • The focus is \mathbf{Focus = (80, -1760)}
  • The directrix is \mathbf{y = \frac{1}{640}}
  • The axis of the symmetry of parabola is: \mathbf{x = 80}

From the question, we have:

\mathbf{Vertex: (h,k) = (80,10)}

\mathbf{Origin: (x,y) = (0,0)}

The equation of a parabola is:

\mathbf{y = a(x - h)^2 + k}

Substitute the values of origin and vertex in \mathbf{y = a(x - h)^2 + k}

\mathbf{0 = a(0 - 80)^2 + 10}

\mathbf{0 = a(- 80)^2 + 10}

\mathbf{0 = 6400a + 10}

Collect like terms

\mathbf{6400a =- 10}

Solve for a

\mathbf{a =- \frac{1}{640}}

Substitute the values of a and the vertex in \mathbf{y = a(x - h)^2 + k}

\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}

The focus of a parabola is:

\mathbf{Focus = (h, \frac{k+1}{4a})}

Substitute the values of a and the vertex in \mathbf{Focus = (h, \frac{k+1}{4a})}

\mathbf{Focus = (80, \frac{10+1}{4 \times -\frac{1}{640}})}

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\mathbf{Focus = (80, -11\times 160)}

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The equation of the directrix is:

\mathbf{y = -a}

So, we have:

\mathbf{y = \frac{1}{640}} ----- the directrix

The axis of symmetry is:

\mathbf{x = -\frac{b}{2a}}

We have:

\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}

Expand

\mathbf{y = -\frac{1}{640}(x^2 -160x + 6400) +10}

Expand

\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x - 10 +10}

\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x }

A quadratic function is represented as:

\mathbf{y = ax^2 + bx + c}

So, we have:

\mathbf{a = -\frac{1}{640}}

\mathbf{b = \frac{1}{4}}

Recall that:

\mathbf{x = -\frac{b}{2a}}

So, we have:

\mathbf{x = -\frac{1/4}{2 \times -1/640}}

\mathbf{x = \frac{1/4}{1/320}}

This gives

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\mathbf{x = 80}

Hence, the axis of the symmetry of parabola is: \mathbf{x = 80}

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