Because since its more complex it has more detail and information to it
Answer:
The mass of water produced is 4.29 g.
Explanation:
Given;
reacting mass of ethane, C₂H₆ = 2.5 g
reacting mass of oxygen, O₂ = 5.0 g
The balanced combustion reaction is given as follows;
2C₂H₆ + 7O₂ ----------------> 4CO₂ + 6H₂O
Based on the balanced equation above;
requires
7.0 moles of oxygen -----------------------> 2.0 moles of ethane
requires
5.0 g of oxygen --------------------------> x gram of ethane
x = (2 x 5) / 7
x = 1.43 g
Ethane is in excess of 1.07g (2.5 g - 1.43g)
Now, determine the mass of water produced by 1.43 g of ethane;
requires
2.0 moles of ethane -----------------------> 6.0 moles of water
requires
1.43 g of ethane --------------------------> y gram of water
y = (6 x 1.43) / 2
y = 4.29 g
Therefore, the mass of water produced is 4.29 g.
Lyman Series Working Formula:
1/λ = RH (1-(1/n^2))
Given:
n = 6
RH = Rydberg's constant = 1.0968x10^7 m^-1
c = speed of light = 3x10^8 m/s
Required:
Frequency (Hertz or cycles per second)
Solution:
To solve for the wavelength λ, we substitute the given in the working formula
1/λ = RH (1-(1/n^2))
1/λ = 1.0968x10^7 m^-1 (1-(1/6^2))
λ = 0.0000000938 m or 93.8 nm
To get the frequency, we will use the formula below.
f = c/λ
We then substitute c or the speed of light,
f = (3x10^8 m/s) / 0.0000000938 m
Therefore,
f = 3.2x10^15 s^-1
<em>ANSWER: Frequency = </em><em /><em>3.2x10^15 s^-1</em>
Answer:
3
Explanation:
3 different elements are found
Mg - magnesium
O -oxygen
H - hydrogen
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mark brainliest
If the volume of 425 grams was 48.0 cm³, simply divide
g/cm³ = 425 g/48 cm³ = 8.85 g/cm³
If using water in water displacement, 1 mL = 1 cm³
8.85 g/cm³ = 8.85 g/mL
This density is most closely aligned with that of B. Copper
Hope I helped!