"The boron-nitrogen interaction in the studied molecules shows some similarities with the N→B bond in the H3N-BH3 molecule, formally understood as covalent-dative. ... The results show that all the studied BN bonds are triple, since three two-center orbitals have been obtained."
"Formation of a dative bond or coordinate bond between ammonia and boron trifluoride. When the nitrogen donates a pair of electrons to share with the boron, the boron gains an octet. ... In addition, a pair of non-bonding electrons becomes bonding; they are delocalized over two atoms and become lower in energy."
Answer:
0.0009765625
Explanation: u just keep doing a half life till it goes to 13 aka
8.0g divided by 2 till you reach to 13 times of a half life ;p
Answer:
a) C4H6+2H2=C4H10
b) 4Na+CF4=4NaF+C
c) 2Na+2NH3=2NaNH2+H2
d) 2H202=2H2O+O2
Explanation:
Try and make sure there is the same number of reactants as products
The value for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
<h3>What is an aqueous reaction in
equilibrium?</h3>
When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.
δG = − R T ln
R = universal gas constant 8.313
δG= 20. 46 kj/mol
T = 298 k or 24.4 in celcius.
substituting the value in the equation.
20. 46 kj/mol = 8.313 × 24.4 in celcius × K
K = 8.313 × 24.4 in celcius / 20. 46 kj/mo
k = 9.91 mol .
Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
Learn more about the aqueous reaction in equilibrium, here:
brainly.com/question/8983893
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Answer:
solid(particles are rightly packed)
liquid(particles are losely packed)
gas(particles move freely)
Explanation:
