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Elan Coil [88]
3 years ago
14

BEST ANSWER GETS BRAINLIEST!!!!

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0
A: 
An independent variable could be how long she works. (Well it's not really independent I guess... Sorta depends.)
A dependent variable could be how much money she makes, depending on how long she works.

B:
Umm, like:
(1, 7)
If 1 was how many hours she worked and $7 is how much money she made, and therefore x would be how many hours she worked and y would be how much total money she made.
(2, 14)
(3, 21)

C: An equation would be 7x = y.
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Please Help,
musickatia [10]
X=6 Z=8 so X:Z =. 6/8 So 2 goes into both 6 and 8 so divide numerator and denominator by 2 which = 3/4
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4 years ago
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X^2+9x+20=0<br><br> What are the steps to solve by factoring?
Dimas [21]
First simplify the equation and next multiply the 20 with the x^2 and find a number that adds together to give you the middle
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4 years ago
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Can some help me with this .
PtichkaEL [24]

Answer:

1. 169π ft²

2. 144π in²

3) 25π yd²

Step-by-step explanation:

1) π * 13²

π * 169

units = ft²

169π ft²

2) π * 12²

π * 144

units = in²

144π in²

3)π * 5²

π * 25

units = yd²

25π yd²

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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3 years ago
If a sprinkler waters 1/15 of a lawn in 1/5 of an hour, how much time will it take to water the entire lawn?
GaryK [48]

Answer:

3 hours

Step-by-step explanation:

To solve this we can first find out how many minutes is 1/5th of an hour which is: 12 mins.

Now we know it will take 15 sets of 12 minutes to water the full lawn so we can multiply 15*12 to get our answer.

15*12 = 180

Now we divide 180 (minutes) by 60 (minutes) to find out how many hours that is:

180/60 = 3 hours

Hope this helped! If possible please leave a thanks so I can continue to help out others :),

comment if you have any questions.

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Find the measure of the unknown angle.
Tomtit [17]

Answer:

131° Degrees

Step-by-step explanation:

It's the same just put in different places

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