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3 years ago

Which is the graph of y=2/(x+1)-6

Mathematics

2 answers:

Mariana [72]3 years ago

8 0

Answer:

A on EDGE2020

krek1111 [17]3 years ago

4 0

Answer:

I have linked the graph in an image

Step-by-step explanation:

1. Simplify y=2/(x+1)-6

2. Subtract the numbers 1-6=-5

3. = 2/x-5

4. Graph your results

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True or False? All equiangular triangles are similar.

OlgaM077 [116]

Answer:

True

Step-by-step explanation:

All equiangular triangles are similar.

4 0

4 years ago

If someone could help me with coordinates, i would really appreciate it.

hichkok12 [17]

Answer:

6.W = -4 , 2 B = -3 , -1 Y = -1 , 1 Z = -2 , 3

7. R = -3 . -2 E = -3 , -4 J = -4 , -4

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3 years ago

Henry and his brother each start a savings account. Henry begins with $200 and deposits $25 each month. His brother begins with

DiKsa [7]

Answer:

5 months

Step-by-step explanation:

Henry

200+25+25+25+25+25= 325

Brother

150+35+35+35+35+35=325

3 0

3 years ago

Compute the number of vinyl tiles, measuring 25 cm each side, needed to tile a kitchen measuring 102 ft. by 18 ft. Try not to ro

nadya68 [22]

Answer: 2730 tiles (Approx)

Step-by-step explanation:

Since, The side length of each side = 25

According to the question the shape of the tile is square.

Thus, the area of one tile = 25 × 25 = 625 $cm^2$

Also, we need to tile a kitchen measuring 102 ft. by 18 ft

Thus, the area of the room in which we have to tile = 102 × 18 = 1836 $feet^2$ = 1836×30.48 × 30.48 = 1705699.8144 $cm^2$

Thus, the total number of the tiles = the area of the room in which we have to tile / the area of one tile = $\frac{1705699.8144}{625} = 2729.11970304$

Since, we must take 2730 tiles to tile the kitchen.

3 0

3 years ago

Read 2 more answers

Solving simultaneous equations with one quadratic, x^2+y^2=16 and y=x+3

Svetlanka [38]

If $y=x+3$ , then in the first equation you have

$x^2+(x+3)^2=x^2+(x^2+6x+9)=2x^2+6x+9=16$

Rewriting a bit, you get

$x^2+3x+\dfrac92=8$

$x^2+3x+\dfrac94+\dfrac94=8$

$\left(x+\dfrac32\right)^2=\dfrac{23}4$

$x=-\dfrac32\pm\dfrac{\sqrt{23}}2$

Now, since $y=x+3$ , you also get

$y=-\dfrac32\pm\dfrac{\sqrt{23}}2+3=\dfrac32\pm\dfrac{\sqrt{23}}2$

So, there are two solutions here:

$(x,y)=\left(-\dfrac32+\dfrac{\sqrt{23}}2,\dfrac32+\dfrac{\sqrt{23}}2\right)$
$(x,y)=\left(-\dfrac32-\dfrac{\sqrt{23}}2,\dfrac32-\dfrac{\sqrt{23}}2\right)$

7 0

3 years ago