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sweet-ann [11.9K]
3 years ago
8

What is the pH of a 5.4 x 10-3 M HCl solution?A. 2.3B. 3.3C. 3.7D. 11.7​

Chemistry
1 answer:
quester [9]3 years ago
8 0

Answer: A. 2.3

Explanation:

pH of a solution is given by the following mathematical expression;

pH = - Log [ H+]

     =  -Log [ 5.4 x 10-3]

     = 3 - 0.7324

pH  = 2.27 aprrox 2.3

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A chemist requires 0.802 mol Na2CO3 for a reaction. How many grams does this correspond to?
Komok [63]

Answer:

Ok:

Explanation:

So grams = mols*MolarMass. Here, MolarMass (MM) = 105.99g which can be found using the periodic table. mols is given to be 0.802. We can then plug in to get that it corresponds to 85.0g.

7 0
3 years ago
What is the concentration in g/L of a solution containing 10 g of solute in 2 L of solution
alekssr [168]

The concentration is 5 g/L.

Concentration = mass/volume = 10 g/2 L = 5 g/L

6 0
3 years ago
Which is the correct answer??
mestny [16]

Answer:

1

Explanation:

8 0
3 years ago
A gas at 400 k is placed in a 4.0 l moveable piston. The gas is cooled to 252 k. What is the new volume of the piston?
katrin [286]

Answer:

2.52L

       

Explanation:

Given parameters:

T₁  = 400K

V₁  = 4L

T₂ = 252K

unknown

V₂ = ?

Solution:

To solve this problem, we are going to apply charle's law. The law states that the volume of a fixed mass of gas is directly proportional to temperature provided pressure is constant.

Mathematically,

               \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

Substitute and solve for V₂

           \frac{4}{400}  = \frac{V_{2} }{252}

        V₂ = 2.52L

         

6 0
3 years ago
Hydrogen gas has a density of 0.090 g/L, and at normal pressure and -1.72 C one mole of it takes up 22.4 L. How would you calcul
BlackZzzverrR [31]

Answer:

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Explanation:

Assuming that all caculations are at normal pressure and -1.72°C :

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Where

n is the number of moles of hydrogen

n is the mass of hydrogen

\rho is the density of hydrogen

6 0
3 years ago
Read 2 more answers
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