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sweet-ann [11.9K]
3 years ago
8

What is the pH of a 5.4 x 10-3 M HCl solution?A. 2.3B. 3.3C. 3.7D. 11.7​

Chemistry
1 answer:
quester [9]3 years ago
8 0

Answer: A. 2.3

Explanation:

pH of a solution is given by the following mathematical expression;

pH = - Log [ H+]

     =  -Log [ 5.4 x 10-3]

     = 3 - 0.7324

pH  = 2.27 aprrox 2.3

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Calculate the pH of a 0.22 M ethylamine solution.
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Answer:

answer is 12.18

Explanation:

(C2H5NH2, Kb = 5.6 x 10-4.)

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What happens to the sugar from a sugar cube after it has dissolved in a cup of tea? (Molecule related)​
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Answer: Sugar is very soluble in water. When you add the solid to the tea the key process is that the solid sugar dissolves in the warm liquid: the solid crystals are broken up into molecules which are every dispersed throughout the existing liquid.

Explanation:

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A shopkeeper has a few bottles of soft drinks in his shop.But,these are not labelled.He has to serve the drinks on the demand on
zepelin [54]

Answer:

He will decide which drink is to be served to whom, by the use of litmus paper.

Explanation:

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5 0
3 years ago
Create the Equation: What is the Percent Yield of Ammonia (NH3) if 11.8 g is recovered in a reaction with 7.02 x 10^23 molecules
insens350 [35]

Answer:

Explanation:

The first thing that you need to do here is to calculate the theoretical yield of the reaction, i.e. what you get if the reaction has a

100

%

yield.

The balanced chemical equation

N

2

(

g

)

+

3

H

2

(

g

)

→

2

NH

3

(

g

)

tells you that every

1

mole of nitrogen gas that takes part in the reaction will consume

3

moles of hydrogen gas and produce

1

mole of ammonia.

In your case, you know that

1

mole of nitrogen gas reacts with

1

mole of hydrogen gas. Since you don't have enough hydrogen gas to ensure that all the moles of nitrogen gas can react

what you need

3 moles H (sub 2)

>

what you have

1 mole H (sub2)

you can say that hydrogen gas will act as a limiting reagent, i.e. it will be completely consumed before all the moles of nitrogen gas will get the chance to take part in the reaction.

So, the reaction will consume

1

mole of hydrogen gas and produce

1

mole H

2

⋅

2 moles NH

3

3

moles H

2

=

0.667 moles NH

3

at

100

%

yield. This represents the reaction's theoretical yield.

Now, you know that the reaction produced

0.50

moles of ammonia. This represents the reaction's actual yield.

In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every

100

moles of ammonia that could theoretically be produced.

You know that

0.667

moles will produce

0.50

moles, so you can say that

100

moles NH

3

.

in theory

⋅

0.50 moles NH

3

.

actual

0.667

moles NH

3

.

in theory

=

75 moles NH

3

.

actual

Therefore, you can say that the reaction has a percent yield equal to

% yield = 75%

−−−−−−−−−−−−−

or 75 moles NH sub3

I'll leave the answer rounded to two sig figs.

5 0
3 years ago
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