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Sidana [21]
3 years ago
9

Antacids are taken to counterbalance excess hydrochloric acid, HCl, in the stomach. Complete and balance the following neutraliz

ation reactions involving various antacid tablets. If there should be only one mole of the product or reagent in the reaction, then leave the option blank. (A blank answer corresponds to 1 and coefficients of 1 are not expressly written in chemical formulas.)
2, 3, CaCl2, CaCl, MgCl2, 4, MgCl (<-------The options to choose from)
______CaCO3+______HCl -----> _______ /_______+_______H2O+_______CO2
Mg(OH)2+ ______HCl------>________ /________+________H2O
Balance each element on each side of the reaction arrow by adding coefficients to the reactants and products.
The antacid Brioschi, which has been used to relieve heartburn, is mainly sodium bicarbonate. Predict the products, then write the balanced neutralization reaction for the antacid Brioschi in the stomach where the main acid present is hydrochloric acid, HCl.
Express your answer as a chemical equation.
Chemistry
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

1. CaCO3 + 2HCl —> CaCl2 + H2O + CO2

2. Mg(OH)2 + 2HCl —> MgCl2 + 2H2O

3. Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

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The substance is followed by H2O
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What is the volume of a 0.1 M HCl solution containing 1.46 moles of HCI?
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N = cv
1.46 = 0.1 x v
v = 1.46/0.1
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Hydrazine (N2H4) is used as rocket fuel. It reacts with oxygen to form nitrogen and water.
Marina86 [1]

Answer:

See explanation below for answers

Explanation:

This is a stochiometry reaction. LEt's write the overall reaction again:

N₂H₄ + O₂ ---------> N₂ + 2H₂O

This reaction is taking place at Standard temperature and pressure conditions (STP) which are P = 1 atm and T = 273 K.  To know the volume of N₂ formed, we need to know first how many moles are formed, and this can be calculated with the reagents and the limiting reagent. Let's calculate the moles first of the reagents:

MM N₂H₄ = 32 g/mol;    MM O₂ = 32 g/mol

mol N₂H₄ = 2000 / 32 = 62.5 moles

mol O₂ ? 2100 / 32 = 65.63 moles

Now that we have the moles, we need to apply the stochiometry and calculate the limiting reagent. According to the overall reaction we have a mole ratio of 1:1 between N₂H₄ and O₂, therefore:

1 mole N₂H₄ ---------> 1 mole O₂

62.5 moles ----------> X

X = 62.5 moles of O₂

But we have 65.63 moles, therefore, the limiting reactant is the N₂H₄.

We also have a 1:1 mole ratio with the N₂, so:

moles N₂H₄ = moles N₂ = 62.5 moles

Now that we have the moles, we can calculate the volume with the ideal gas equation:

PV = nRT

V = nRT / P

R: gas constant (0.082 L atm / K mol)

Replacing we have:

v = 62.5 * 0.082 * 273 / 1

V = 1399.13 L of N₂

Now, how many grams of the excess remains?, we know how many moles are reacting so, let's see how much is left:

moles remaining = 65.63 - 62.5 = 3.12 moles

then the mass of oxygen:

m = 3.12 * 32 = 100.16 g of O₂

7 0
3 years ago
Read 2 more answers
Which of the following is
AleksandrR [38]

Answer:

distance and time are needed to find velocity

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3 years ago
One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su
solong [7]

Answer:

89.55~\%~of~Fe_2O_3~in~the~sample

Explanation:

The first step in this reaction is the<u> converstion from Kg</u> of Fe <u>to</u>  <u>grams</u> of Fe_2O_3.

1.19x10^3~Kg~Fe~\frac{1000g~Fe}{1~Kg~Fe}~\frac{1~mol~Fe}{55.84~g~Fe}~\frac{1~mol~Fe_2O_3}{2~mol~Fe}~\frac{159.68~g~Fe_2O_3}{1~mol~Fe_2O_3}~\frac{1~Kg~Fe_2O_3}{1000~g~Fe_2O_3}

X~=~1.7x10^3~Kg~Fe_2O_3

Then we can calculate the <u>percentage</u> of  Fe_2O_3 in the sample:

\%~Fe_2O_3~=~\frac{1.7x10^3~Kg~Fe_2O_3}{1.9x10^3~Kg~Sample}*100

89.55~\%~of~Fe_2O_3~in~the~sample

3 0
3 years ago
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