Any help would be appreciated! :)
1 answer:
You might be interested in
Answer:
(a) The energy of the photon is 1.632 x J.
(b) The wavelength of the photon is 1.2 x m.
(c) The frequency of the photon is 2.47 x Hz.
Explanation:
Let;
= -13.60 ev
= -3.40 ev
(a) Energy of the emitted photon can be determined as;
-
= -3.40 - (-13.60)
= -3.40 + 13.60
= 10.20 eV
= 10.20(1.6 x )
-
= 1.632 x
Joules
The energy of the emitted photon is 10.20 eV (or 1.632 x Joules).
(b) The wavelength, λ, can be determined as;
E = (hc)/ λ
where: E is the energy of the photon, h is the Planck's constant (6.6 x Js), c is the speed of light (3 x
m/s) and λ is the wavelength.
10.20(1.6 x ) = (6.6 x
* 3 x
)/ λ
λ =
= 1.213 x
Wavelength of the photon is 1.2 x m.
(c) The frequency can be determined by;
E = hf
where f is the frequency of the photon.
1.632 x = 6.6 x
x f
f =
= 2.47 x Hz
Frequency of the emitted photon is 2.47 x Hz.
Answer:
Initial speed of the spaceship 1, v = 2 m/s
Explanation:
Given that :
Mass of spaceship 1 and 2 that have equal mass are 300 kg
Initial momentum of the spaceship 1 is 600 kg-m/s
To find :
We need to find the initial momentum of spaceship 1.
Solve :
The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :
v = 2 m/s
Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.