Answer:
The Total Momentum before and after collision remains the same.
Explanation:
Note that the balls have the same masses.
A moving cue ball has an initial momentum. After every collision with another stationary ball, the momentum, which is the product of their mass and velocity, of the balls is conserved. This simply means that the total momentum before the collision is the same as the total momentum after the collision.
This also means that the energy must be conserved as well. The balls cannot fling away from each other with more energy than you give them.
Answer:
a) -2.1731 m⁻s
Explanation:
L= length of thread, H= height of ball from ceiling,
N/B h= l cosФ, Ф=31°, l=2.7m, g=9.8m⁻s, m= 6kg
Required to find speed v, of the ball in m⁻s
ω=√g/h, =√g/lcosФ
⇒ ω=√9.8/2.7×cos31°
= 1.992rad⁻s
Now, speed in m/s, v= r.ω
where tanФ= r/h ⇒
r= h×cos 31°
r= 2.7 × cos(31) × tan(31) =-1.0909m
v= 1.992× -1.0909 = -2.1731 m/s
Answer:
Planet Y
Rx = 1.587 Ry
Explanation:
Tx = 290 days
Ty = 145 days
Let the semi major axis of planet X is Rx and of plant Y is Ry.
According to the Kepler's third law of planetary motion
Rx = 1.587 Ry
So, planet Y is closest to star.
<u>Answer:</u>
Speed of Hawk's shadow on the level ground = 3.29 m/s
<u>Explanation:</u>
When the sun is directly above the head of hawk shadow will be directly below hawk. So the speed of hawk's shadow will be equal to speed of hawk's in X -direction.
Velocity of hawk = 5.35 m/s
Angle from horizontal = 52.00⁰
Horizontal component = 5.35 cos 52.00⁰ = 3.29 m/s
So speed of hawk's shadow = 3.29 m/s
Answer:
t = 0.657 s
Explanation:
First, let's use the appropiate equations to solve this:
V = √T/u
This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.
Where:
V: Speed of the disturbance
T: Tension of the rope
u: linear density of the rope.
The density of the rope can be calculated using the following expression:
u = M/L
Where:
M: mass of the rope
L: Length of the rope.
We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:
u = 2.31 / 10.4 = 0.222 kg/m
Now, replacing in the first equation:
V = √55.7/0.222 = √250.9
V = 15.84 m/s
Finally the time can be calculated with the following expression:
V = L/t ----> t = L/V
Replacing:
t = 10.4 / 15.84
t = 0.657 s