Answer: 123
Step-by-step explanation: TO solve problems like this, you should assign a variable to the lowest number, lets just say n. From here, since we know the numbers are consecutive, we can see that the numbers are n, n+1, and n+2. Therefore:
n(first number) + (n+1)(second number) +(n+2) (3rd number) =366
>n+n+1+n+2=366
3n+3=366
3n=363
n=121
n+2=123
If the series is made up of numbers in an arithmetic progression, you have

where

is the first term and

is the common difference between terms.
Since the last term in the series is

, you have

Solve the system

and you'll find that the first term is

(with

).
Evaluate 3x for x = −2, x = 1, and x = 3. Question 18 options: A) 1∕3, 0, 9 B) 1∕9, 3, 27 C) 9, 3, 27 D) 1∕9, 9, 27
icang [17]
Answer: B) 1/9, 3, 27
Step-by-step explanation:
Here, we need to evaluate
for 
So, we substitute values of x in the given function.
At x= -2, we have
![3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}\ \ \ [\because\ a^{-n}=\dfrac{1}{a^n}]](https://tex.z-dn.net/?f=3%5E%7B-2%7D%3D%5Cdfrac%7B1%7D%7B3%5E2%7D%3D%5Cdfrac%7B1%7D%7B9%7D%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D%5D)
At x= 1, we have

At x= 3

So, the values of
for
Thus, the correct answer is B) 1/9, 3, 27
These three individual items take 1/4, 1/6, and 1/8 of the budget. The part of the budget that they take all together is the sum of those individual parts. You need to add up 1/4, 1/6, and 1/8. To do that, you'll need to put all three fractions over a common denominator first, the