Distance, as far as i know
Answer:
idk but you should try getting photo math it's a
app that helps you with math
Answer: x=3 and y=5
Step-by-step explanation: 11x-6y=3, 5x-8y=-25
11x-6y+6y=3+6y
11x/11=3/11+6y/11
x=3+6y/11
5(3+6y/11)-8y(11)/11
5(6y+3)-88y/11
30y+15-88y/11
88y-30y
58y
11(15-58y)/11=11(-25)
15-58y-15=-275-15
-58y/-58=-290/-58
y=5
x=3+6(5)/11
3+30
33
33/11
x=3
x=3, y=5
Given:
0.1% of all transactions are fraudulent
99% correct identification whether a transaction is fraudulent or not.
Scanned 5,000,000 transactions.
5,000,000 x 0.1% = 5,000 fraudulent transactions.
For me, there are 5,000 fraudulent transactions. This is based on the 0.1% rather than the 99%. Because the problem clearly states that the 0.1% of ALL transaction is identified as fraudulent. The 99% of the computer program only deals with the correct identification of the transaction as either fraudulent or not. For me, it is not a clear measure of the true number of fraudulent transactions.
Answer:
The river is 3.15 feet deep.
Step-by-step explanation:
First let's recognize what we need to find: the depth of the river
We know last year the river was 4.2 feet deep, but it dropped 25%. This means we also need to find how much it dropped. To find this, we need to know what 25% of 4.2 is. Write an equation for this.
y = 25% of 4.2
y = 0.25 • 4.2
y = 1.05
This means that the river dropped 1.05 feet. To know its depth now, we need to subtract 1.05 from 4.2. Write an equation for this.
d = 4.2 - 1.05
d = 3.15
The river is 3.15 feet deep.
Hope this helps!
