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Gemiola [76]
3 years ago
7

Alex has had 15 spelling quizzes. He has scored 80, 85, 80, 75, 90, 95, 85, 90, 95,

Mathematics
1 answer:
Alina [70]3 years ago
7 0
The answer to this is the second box, I hope this helped you
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In a movie theater, there are children and adults in the ratio 4:7. If there are 21 adults, how many people total are there in t
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Answer:

33

Step-by-step explanation:

7x3=21

4x3=12

21+12=33

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What is 3 3/4 divided by 2/8
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The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
forsale [732]

Answer:

a)

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = 3.37*10^{-2} meters per second squared

b)

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = 2.92*10^{-2} meters per second squared

Step-by-step explanation:

The formula is:

v=\frac{2 \pi R}{T}

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

a_c=\frac{4 \pi^{2} R}{T^2}

Now,

a)

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}

Centripetal Acceleration at Equator = 3.37*10^{-2} meters per second squared

b)

At 30.0° north of the equator:

R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6

Now,

Speed = v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}

Centripetal Acceleration at 30 degrees north of equator = 2.92*10^{-2} meters per second squared

4 0
3 years ago
Multi-step equations solve the equation
S_A_V [24]
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3 years ago
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