Answer:

Step-by-step explanation:
The terms of this sum make the arithmetic sequence.
The fomula of a sum of <em>n</em> terms of an arithmetic sequence:
![S_n=\dfrac{[2a_1+(n-1)d]\cdot n}{2}](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7B%5B2a_1%2B%28n-1%29d%5D%5Ccdot%20n%7D%7B2%7D)
We have

Substitute:
![S_{50}=\dfrac{[2\cdot2+(50-1)\cdot15]\cdot50}{2}=(4+49\cdot15)\cdot25=(4+735)\cdot25\\\\=739\cdot25=18,475](https://tex.z-dn.net/?f=S_%7B50%7D%3D%5Cdfrac%7B%5B2%5Ccdot2%2B%2850-1%29%5Ccdot15%5D%5Ccdot50%7D%7B2%7D%3D%284%2B49%5Ccdot15%29%5Ccdot25%3D%284%2B735%29%5Ccdot25%5C%5C%5C%5C%3D739%5Ccdot25%3D18%2C475)
Answer:
x = -2
∠A = 35
Step-by-step explanation:
x + 37 + x + 57 = 90
reduce:
2x = -4
x = -2
∠A = 37-2 = 35
Let, the number = x
It would be: x * 96% = 42
x * 0.96 = 42
x = 42 / 0.96
x = 43.75
In short, Your Answer would be 43.75
Hope this helps!
If <em>z</em> ⁷ = 128<em>i</em>, then there are 7 complex numbers <em>z</em> that satisfy this equation.

![\implies z=\sqrt[7]{2^7} e^{i\frac17\left(\frac\pi2+2n\pi\right)}](https://tex.z-dn.net/?f=%5Cimplies%20z%3D%5Csqrt%5B7%5D%7B2%5E7%7D%20e%5E%7Bi%5Cfrac17%5Cleft%28%5Cfrac%5Cpi2%2B2n%5Cpi%5Cright%29%7D)
(where <em>n</em> = 0, 1, 2, …, 6)


Yes, because you need to remember and/or list out your square roots no matter what.