Answer
is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.
V(N₂O) = 8.4 L.
V(N₂O) =
n(N₂O) · Vm.
Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.
n(N₂O) = 8.4 L ÷ 22.4 L/mol.
n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>
Answer:
A molecular compound is usually composed of two or more nonmetal elements. Molecular compounds are named with the first element first and then the second element by using the stem of the element name plus the suffix -ide.
Gasoline contains C and H atoms. During combustion, the carbon (C) from the fuel combines with oxygen (O2) from the air to produce carbon dioxide (CO2).
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O.
Combustion reactions release large amounts of heat. They have negative enthalpy. A negative enthalpy represents an exothermic reaction, releasing heat. This reaction is spontaneous and exothermic, since we can obtain energy from the reaction; the ΔG (free energy) is negative (So 1 is true).
ΔG < 0, so the free energy of the system decreases with the reaction. Remember that when there is a negative ΔG the reaction goes from higher free energy to lower free energy, like in this case.
1. H₂SO₄ + 2NH₄OH ⟶ (NH₄)₂SO₄ + 2H₂O
2. 2NaOH + H₂CO₃ ⟶ Na₂CO₃ + 2H₂O
3. HNO₃ + KOH ⟶ KNO₃ + H₂O
<em>Explanation</em>:
Acid + base ⟶ salt + water
Take the H from the acid and the OH from the base to get water.
Then, join what’s left to get the salt. Write the symbol for the metal first.
For example, in equation 3, take the H from HNO₃ and the OH from KOH.
Combining the remaining parts (NO₃ and K) to get the salt, KNO₃.
Answer : The equilibrium constant for this reaction is, 
Explanation :
The given main chemical reaction is:
; 
The intermediate reactions are:
(1) 
; 
(2) 
; 
We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:
(1) 
; 
(2) 
; 
Thus, the equilibrium constant for this reaction will be:
Thus, the equilibrium constant for this reaction is,
