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xxMikexx [17]
3 years ago
7

Name the compound: PbF3

Chemistry
2 answers:
Liono4ka [1.6K]3 years ago
6 0
The answer is;
Lead(III) Fluoride
alina1380 [7]3 years ago
5 0

Answer:

Lead(III) Fluoride PbF3 Molecular Weight -- EndMemo.

Explanation:

paki brainly po tysm

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The amount of kinetic energy an object has depends on its:
UkoKoshka [18]

Answer:

the 4th one

Explanation:

kinitc energy formula is1/2mv^

there is mass ,and velocity (speed)

I hope it help

3 0
2 years ago
Read 2 more answers
2. Extract the relevant information from the question: NaOH V = 30 mL , M = 0.10 M HCl V = 25.0 mL, M = ?
Andrei [34K]

Answer:

0.12M

Explanation:

A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

HCl + NaOH —> NaCl + H2O

From the above equation,

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) = 30mL

Mb (Molarity of the base) = 0.1M

Va (volume of the acid) = 25mL

Ma (Molarity of the acid) =?

The molarity of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 25/ 0.1 x 30 = 1

Cross multiply to express in linear form

Ma x 25 = 0.1 x 30

Divide both side by 25

Ma = (0.1 x 30) / 25

Ma = 0.12M

The molarity of the acid is 0.12M

5 0
3 years ago
Examples<br> 1) How many atoms of silver are there in 4.5 moles of silver? [Ag = 107.8682 g/mol]
Anon25 [30]
3.0x10-4..............................
7 0
3 years ago
Read 2 more answers
Why does the hull of an ocean -going ship rust quickly?
stepan [7]
Metal rusts when it oxidized around moisture.
4 0
2 years ago
Help in chem please!!!!!!
IgorLugansk [536]

This is a one-step unit analysis problem.  Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

3 0
3 years ago
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