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2 years ago

Who has padle t wana join mine

Mathematics

2 answers:

valkas [14]2 years ago

4 0

Answer:

what?

Step-by-step explanation:

frutty [35]2 years ago

3 0

Answer:

meh heres a code if u want to join mine to or hers also fin

Step-by-step explanation:

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Does the (1,2) satisfy the equation Y equals 3X

AlekseyPX

No. When you plug in x and y you get 2=3

8 0

3 years ago

which of the following plotted points on the graph represent the zeros of the function g(x) = (x^2 - 3x - 10)(x + 4)

Natalka [10]

Answer: The answer would be (-2,0),(-4,0), and (5,0)

Step-by-step explanation:

Guessing the answer choices are

(-2,0)

(4,0)

(0,10)

(-4,0)

(0,-2)

(0,-10)

(5,0)

3 0

2 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$