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3 years ago

Helpppppp me please!!!!

Mathematics

2 answers:

KengaRu [80]3 years ago

7 0

10 * (-2)^3 *(-3)^2
10 * -8 * 9 =
-720
answer: -720

Svetlanka [38]3 years ago

7 0

You’re answer is 720

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The length of a bridge on a map is 1.5 cm. What is the actual length of the bridge in meters if the map is drawn at a scale of 1

Ilya [14]

Answer:

Step-by-step explanation:

If the length of a bridge on a map is 1 cm,then the actual length = 40,000

If the length of a bridge on a map is 1.5 cm,then the actual length= 1.5 * 40000

= 60000.0 = 60,000 m

3 0

3 years ago

Ship Co. produces storage crates that require 1.2 meters of material at $.85 per meter and 01 direct labor hours at $15.00 per h

Vesna [10]

Answer:

$3.42

Step-by-step explanation:

Meters of material required = 1.2 meters

Cost per meter of material = $0.85

Direct labor hours = 0.1

Cost of direct labor per hour = $15

Overhead rate = $9 per direct labor hour

Standard cost per unit of product :

(Direct material cost per unit + direct labor cost per unit + overhead cost per unit)

Direct material cost per unit :

Material needed × cost per meter = (1.2 × $0.85) = $1.02

Direct labor cost per unit :

Direct labor hour × cost per hour = ( 0.1 × $15) = $1.5

Overhead cost:

0.1 * $9 = $0.9

Standard cost :

($1.02 + $1.5 + $0.9) = $3.42

5 0

3 years ago

Joe, John and Jason are each a year apart in age. If the

-Dominant- [34]

Answer:

Jason is 14 year old.

Step-by-step explanation:

Given: Joe, John and Jason are each a year apart in age.

Sum of their age is 39.

Lets assume the age of Joe be x

∴ Age of Jahn will be $(x+1)$

And age of Jason will be $(x+2)$

Now, putting up an equation for the sum of their age.

∴ $x+(x+1)+(x+2)= 39$

Opening the parenthesis.

⇒ $x+x+1+x+2= 39$

⇒ $3x+3= 39$

Subtracting both side by 3

⇒ $3x= 36$

Dividing both side by 3

⇒ $x= \frac{36}{3}$

∴ $x= 12\ years$

Hence, Joe is 12 year old.

Next subtituting the value of x to find age of Jason and John.

Jason= $(x+2)= 12+2$

∴Jason= 14 years.

John age= $(x+1)= 12+1$

∴ John Age= 13 years.

Hence, Jason is 14 year of age.

5 0

3 years ago

A study of 4,430 U.S. adults found that 2,913 were obese or overweight. The 95% confidence interval for the proportion of adults

IrinaK [193]

Answer:

$0.658 - 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.644$

$0.658 + 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.672$

We are 95% confident that the true proportion of adults overweight is between 0.644 and 0.672

Step-by-step explanation:

We can begin founding the estimated proportion of people overweight:

$\hat p =\frac{2913}{4430}= 0.658$

We need to find a critical value for the confidence level using the normal standard distribution. We know that 95% is the confidence level, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: