In triangel abc line segmemt cd is an altitude, such that ad=bc. find ac if ab=3cm and cd =sqrt2
1 answer:
Answer:
√7
Step-by-step explanation:
Let :
AC = x
BD = y ; AD = 3 - y
Since, AD = BC
Then BC = 3 - y
Taking △BDC a d applying Pythagoras
Hypotenus² = opposite² + adjacent²
BC² = CD² + BD²
(3 - y)² = (√3)² + y²
9 - 6y + y² = 3 + y²
-6y + y² - y² = 3 - 9
-6y = - 6
y = 1
AD = 3 - y ; AD = 3 - 1 = 2
Taking △ADC
AC² = CD² + AD²
AC² = (√3)² + 2²
AC² = 3 + 4
AC² = 7
AC = √7
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Answer:
- m ≤ 7
Step-by-step explanation:
<u>Let's simplify the inequality.</u>
- -6(m - 3) ≥ -24
- => -6m + 18 ≥ -24
- => 24 + 18 ≥ 6m
- => 42 ≥ 6m
- => 42/6 ≥ 6m/6
- => (7 ≥ m) = (m ≤ 7)
Option C is correct.
