In triangel abc line segmemt cd is an altitude, such that ad=bc. find ac if ab=3cm and cd =sqrt2
1 answer:
Answer:
√7
Step-by-step explanation:
Let :
AC = x
BD = y ; AD = 3 - y
Since, AD = BC
Then BC = 3 - y
Taking △BDC a d applying Pythagoras
Hypotenus² = opposite² + adjacent²
BC² = CD² + BD²
(3 - y)² = (√3)² + y²
9 - 6y + y² = 3 + y²
-6y + y² - y² = 3 - 9
-6y = - 6
y = 1
AD = 3 - y ; AD = 3 - 1 = 2
Taking △ADC
AC² = CD² + AD²
AC² = (√3)² + 2²
AC² = 3 + 4
AC² = 7
AC = √7
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Answer:
E. 5
Step-by-step explanation:
Let's rewrite the equation in the form of y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).
2x + y = 5
y = -2x+5
M, the slope, is -2
<u>5, b, is the y-intercept</u>
See attached graph.
