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kaheart [24]
2 years ago
5

In triangel abc line segmemt cd is an altitude, such that ad=bc. find ac if ab=3cm and cd =sqrt2

Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

√7

Step-by-step explanation:

Let :

AC = x

BD = y ; AD = 3 - y

Since, AD = BC

Then BC = 3 - y

Taking △BDC a d applying Pythagoras

Hypotenus² = opposite² + adjacent²

BC² = CD² + BD²

(3 - y)² = (√3)² + y²

9 - 6y + y² = 3 + y²

-6y + y² - y² = 3 - 9

-6y = - 6

y = 1

AD = 3 - y ; AD = 3 - 1 = 2

Taking △ADC

AC² = CD² + AD²

AC² = (√3)² + 2²

AC² = 3 + 4

AC² = 7

AC = √7

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]Answer:

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Substitute the value of the variable into the equation and simplify.

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4 0
3 years ago
Is the answer 3, 4, 5, or 6? need answer asap please! :)
-BARSIC- [3]
Don't touch the center. It is already even. 
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Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
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3 <<<< answer
4 0
3 years ago
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Mademuasel [1]
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
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Solving for x;
\frac{x}{5} = \frac{2}{3}
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\frac{x}{y} = \frac{10/3}{15/2}
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dalvyx [7]
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