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Fittoniya [83]
3 years ago
9

3|1/2x + 5| + 7 = 5

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

<em>x is -34/3 and -26/3</em>

Step-by-step explanation:

Given the expression

3|1/2x+5| + 7 = 5

Removing the modulus sign

3(1/2x+5) + 7 = 5

Subtract 7 from both sides

3(1/2x+5) + 7 - 7= 5 - 7

3(1/2x+5) = -2

Open the bracket

3/2 x + 15 = -2

Subtract 15 from both sides

3/2 x + 15-15 = -2 - 15

3/2 x = -17

3x = -2*17

3x  = -34

x = -34/3

<em>Hence the value of x is -34/3</em>

<em>For the negative function:</em>

3(1/2x+5) + 7 = 5

Subtract 7 from both sides

3(-(1/2x+5)) + 7 - 7= 5 - 7

3(-1/2x-5) = -2

Open the bracket

-3/2 x - 15 = -2

Add 15 from both sides

3/2 x + 15-15 = -2 + 15

-3/2 x = 13

-3x = 2 * 13

-3x  =26

x = -26/3

<em>Hence the value of x is -26/3</em>

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Step-by-step explanation:

we are given

the sum,common difference and nth term of a geometric sequence

we want to figure out the first term

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\displaystyle S_{ \text{n}} =  \frac{ a_{1}(1 -  {r}^{n} )}{1 - r}

we are given that

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thus substitute:

\displaystyle 189=  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{1 -  \frac{1}{2} }

to figure out a_1 we need to figure out the equation

simplify denominator:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2}  }  = 189

simplify square:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{8} )}^{} )}{ \dfrac{1}{2}  }  = 189

simplify substraction:

\displaystyle  \frac{ a_{1} (\frac{7}{8} )}{ \frac{1}{2}  }  = 189

simplify complex fraction:

\displaystyle   a_{1} (\frac{7}{8} ) \div { \frac{1}{2}  }  = 189

calculate reciprocal:

\displaystyle   a_{1} \frac{7}{8}   \times 2  = 189

reduce fraction:

\displaystyle   a_{1} \frac{7}{4}   \  = 189

multiply both sides by 4/7:

\displaystyle   a_{1} \frac{7}{4}  \times  \frac{4}{7}   \  = 189 \times  \frac{4}{7}

reduce fraction:

\displaystyle   a_{1}     = 27\times  4

simplify multiplication:

\displaystyle  a_{1}    = 108

hence,

\displaystyle  a_{1}    = 108

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