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Fittoniya [83]
3 years ago
9

3|1/2x + 5| + 7 = 5

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

<em>x is -34/3 and -26/3</em>

Step-by-step explanation:

Given the expression

3|1/2x+5| + 7 = 5

Removing the modulus sign

3(1/2x+5) + 7 = 5

Subtract 7 from both sides

3(1/2x+5) + 7 - 7= 5 - 7

3(1/2x+5) = -2

Open the bracket

3/2 x + 15 = -2

Subtract 15 from both sides

3/2 x + 15-15 = -2 - 15

3/2 x = -17

3x = -2*17

3x  = -34

x = -34/3

<em>Hence the value of x is -34/3</em>

<em>For the negative function:</em>

3(1/2x+5) + 7 = 5

Subtract 7 from both sides

3(-(1/2x+5)) + 7 - 7= 5 - 7

3(-1/2x-5) = -2

Open the bracket

-3/2 x - 15 = -2

Add 15 from both sides

3/2 x + 15-15 = -2 + 15

-3/2 x = 13

-3x = 2 * 13

-3x  =26

x = -26/3

<em>Hence the value of x is -26/3</em>

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General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
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<u>Algebra I</u>

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<u>Step 1: Define systems</u>

-5x - 3y = 12

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<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                              -5x - 3(x - 12) = 12
  2. Distribute -3:                                 -5x - 3x + 36 = 12
  3. Combine like terms:                     -8x + 36 = 12
  4. Isolate <em>x</em> term:                               -8x = -24
  5. Isolate <em>x</em>:                                        x = 3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    y = x - 12
  2. Substitute in <em>x</em>:                                     y = 3 - 12
  3. Subtract:                                               y = -9

<u>Step 4: Graph systems</u>

<em>Check the solution set.</em>

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