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Fittoniya [83]
3 years ago
9

3|1/2x + 5| + 7 = 5

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

<em>x is -34/3 and -26/3</em>

Step-by-step explanation:

Given the expression

3|1/2x+5| + 7 = 5

Removing the modulus sign

3(1/2x+5) + 7 = 5

Subtract 7 from both sides

3(1/2x+5) + 7 - 7= 5 - 7

3(1/2x+5) = -2

Open the bracket

3/2 x + 15 = -2

Subtract 15 from both sides

3/2 x + 15-15 = -2 - 15

3/2 x = -17

3x = -2*17

3x  = -34

x = -34/3

<em>Hence the value of x is -34/3</em>

<em>For the negative function:</em>

3(1/2x+5) + 7 = 5

Subtract 7 from both sides

3(-(1/2x+5)) + 7 - 7= 5 - 7

3(-1/2x-5) = -2

Open the bracket

-3/2 x - 15 = -2

Add 15 from both sides

3/2 x + 15-15 = -2 + 15

-3/2 x = 13

-3x = 2 * 13

-3x  =26

x = -26/3

<em>Hence the value of x is -26/3</em>

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Step-by-step explanation:

Let x and y represent the tens and ones digits, respectively. The 5 times the sum of digits is 5(x+y). The value of the digit-reversed number is (10y+x), so the required relation is ...

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<em>Additional comment</em>

You can solve these equations in any of a variety of ways. Using a graphing calculator to find integer solutions is fast and easy, so is one of my favorites. Here, the coefficients on one equation are not easy multiples of those in the other, so substitution and/or elimination can get messy. In this situation, I like to use the "cross-multiplication" method, which starts with the equations in general form:

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From the coefficients of these equations, differences of cross products are formed:

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Then the solutions are the solutions to 1/d1 = x/d2 = y/d3:

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