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3 years ago

5

A streetlamp has a 20 ft shadow that makes a 40° angle with the ground. which expression represents the height of the street lam

p in feet ?

1 answer:

Oduvanchick [21]3 years ago

6 0

Answer:

20 sin 40° ≈ 12.86 ft

Step-by-step explanation:

Let the height of the street lamp be x

Opposite angle is 40° and the shadow, the hypotenuse of the formed triangle is 20 ft.

sin 40° = x/20
x = 20sin 40°
x ≈ 12.86 ft

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The answer is 144 m 2, hope this helps!!!:)

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3 years ago

4. Write an equation for the line that is parallel to the given line and that passes

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Answer:

$y=\frac{5}{2}x-14$

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

<u>1) Determine the slope (m)</u>

$y=\frac{5}{2}x-10$

In the given equation, $\frac{5}{2}$ is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of $\frac{5}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{5}{2}x+b$

<u>2) Determine the y-intercept (b)</u>

$y=\frac{5}{2}x+b$

Plug in the given point (-6,-29) and solve for b

$-29=\frac{5}{2}(-6)+b$

Simplify -6 and 2

$-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b$

Add 15 to both sides to isolate b

$-29+15=-15+b+15\\-14=b$

Therefore, the y-intercept is -14. Plug this back into $y=\frac{5}{2}x+b$ :

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3 years ago

The state medical school has discovered a new test for tuberculosis. (If the test indicates a person has tuberculosis, the

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The probability according to the given scenario is:

(a) <em>0.0395</em>

(b) <em>0.95</em>

(c) <em>0.076</em>

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$P(B/A) = 0.79$
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(a)

The probability that the b/w has tuberculosis as well as having (+) test will be:

→ $P(A \cap B) = P(B/A).P(A)$

By substituting the values, we get

→ $= 0.79\times 0.05$

→ $= 0.0395$

(b)

The probability that a person does not have tuberculosis will be:

→ $P(A') = 1-P(A)$

→ $=1-0.05$

→ $= 0.95$

(c)

The person does not have tuberculosis as well as have a (+) test, the probability will be:

→ $P(A' \cap B) = P(A').P(B/A')$

→ $= 0.95\times 0.08$

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2 years ago

How to solve 4x-c=k solve for x

Tresset [83]

Answer:

$x = \frac{k + c}{4}$

Step-by-step explanation:

<em><u>Given:</u></em>

$4x - c = k$

<em><u>Solve for:</u></em>

$x$

<em><u>Solution:</u></em>

(1) Let's move all of components that do not contain $x$ (our target) to the right side (notice the change of sign of $c$ from negative to positive):

$4x = k + c$

(2) Let's divide both sides of equation by 4:

$\frac{4x}{4} = \frac{k + c}{4}$

(3) Now, we simplify the left side:

$x = \frac{k + c}{4}$

This is the solution.

Hope this helps!

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4 years ago

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lbvjy [14]

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3 years ago