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dem82 [27]
3 years ago
8

Calculate the length of the third side of this triangle. 6 cm, 8 cm

Mathematics
1 answer:
stiv31 [10]3 years ago
7 0
<h2><em>By</em><em> </em><em> </em><em>pythagoras</em><em> </em><em>theoram</em><em> </em></h2>

<em>c =  \sqrt{a2 + b2}</em>

<em>6</em><em>²</em><em>--</em><em> </em><em>8</em><em>²</em>

<em>1</em><em>8</em><em>-</em><em>-</em><em>1</em><em>6</em>

<em>2</em><em> </em>

<em>Hence</em><em> </em><em>the</em><em> </em><em>third</em><em> </em><em>value</em><em> </em><em>2</em><em> </em>

Step-by-step explanation:

<em><u>I</u></em><em><u> </u></em><em><u>think</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em>

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For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?
Klio2033 [76]

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.  

4 0
2 years ago
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Use the x-intercept method to find all real solutions of the equation.<br> x^3-8x^2+9x+18=0
meriva

Answer:

a. x=-1,3,\:or\:6

Step-by-step explanation:

The given equation is;

x^3-8x^2+9x+18=0

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator or software.

The corresponding function is

f(x)=x^3-8x^2+9x+18

The solution to x^3-8x^2+9x+18=0 is where the graph touches the x-axis.

We can see from the graph  that; the x-intercepts are;

(-1,0),(3,0) and (6,0).

Therefore the real solutions are:

x=-1,3,\:or\:6

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Answer:

This app is meant for 1 question at a time

Step-by-step explanation:

Not trying to be mean just saying, here's a funny cat picture

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Hi mate!

The answer after simplifying is: 2x^2-6x+7

Please let me know if you need further assistance! Have a terrific evening.
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3 years ago
Solve the problem by entering and solving an equation.
geniusboy [140]

Given : A rectangular picture frame has a perimeter of 52 inches. The height of the frame is 12 inches.

To Find : The width of the frame .

Solution : Let us take the width of the frame be x . So , we know the formula to find the perimeter of rectangle as ;

\boxed{\red{\bf Perimeter_{rectangle}=2(l+b)}}

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⇒ Perimeter = 2 ( l + b ) .

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<u>Henc</u><u>e</u><u> the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>recta</u><u>ngle</u><u> </u><u>is</u><u> </u><u>1</u><u>4</u><u> </u><u>inches</u><u>.</u>

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