Answer:
Step-by-step explanation:
Given
Weight of Pinata = 11/4 lb
Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4
Required
Weight of Pinata when filled with candies
To solve this question, we simply need to add all weights together
First, we need to add up the weight of the candies
Take LCM
Simplify:
Next; Add the weight of the candies to the weight of pinata
Take LCM
Simplify
<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>
Answer:
x = -3
Step-by-step explanation:
Okay, the first thing to do is get that 8 away from the fraction. How can we do it? When you have 2³ you have 8, is the same thing, so let's do it:
2³⁰/(2³)⁹ = 2^x
When you have a number with the shape (a^x)^y, you can write it as a^(x•y), so:
(2³)⁹ = 2^3•9 = 2²⁷
Now we have:
2³⁰/2²⁷ = 2^x
When you have a division like this: (a^x)/(a^y), you can write it as a^(x-y), so:
2^(30-27) = 2^x
2^-3 = 2^x
Now you know that x = -3
Answer:
15 trucks
Step-by-step explanation:
If there are a total of 60 vehicles, and 1/4 of them are trucks, we can multiply 60 by 1/4 to get our answer. Or because 1/4 is split into fourths, we can divide 60 by 4 to also get our answer.
Hope this helps!
Answer:
3
Step-by-step explanation:
Formula:
= 3
Answer:
x = 3
y = 2
Step-by-step explanation:
Diagonals of a parallelogram bisect each other into two equal segments. Therefore:
3x - 1 = 2(x + 1)
Solve for x
3x - 1 = 2x + 2
Collect like terms
3x - 2x = 1 + 2
x = 3
Also:
5y + 1 = 6y - 1
Collect like terms
5y - 6y = -1 - 1
-y = -2
Divide both sides by -1
y = -2/-1
y = 2
