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yan [13]
3 years ago
5

(05.05) Which of the following inequalities matches the graph? (1 point)​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer: Choice C.  y \ge -1

==========================================================

Explanation:

The boundary line is a solid line and it's horizontal. Every point on the boundary line has y coordinate -1. So y = -1 is the equation of the boundary line. We can write it as y = 0x-1.

The shading is above the boundary line, so the inequality is y \ge -1

Any point (x,y) in the shaded region has y coordinate that is y = -1 or greater.

For example, the point (0,2) in the shaded region has y coordinate y = 2, and it satisfies the inequality y \ge -1 because 2 \ge -1 is a true statement.

Note: the boundary line is solid, so any point on the boundary line is part of the shaded solution set. This is due to the "or equal to" as part of the inequality sign.

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Let f be a functions of degree 4 whose coefficients are real numbers: two of its zeros are - 3 and 4 - i. Explain why one of the
kvasek [131]

Answer:

Step-by-step explanation:

We have the following theorem, if f is a polynomial with real coefficients, we can factor it completely in factors of the degree at most 2.

Consider first a polynomial of degree two, hence it is a polynomial of the form ax^2+bx+c. The cuadratic formula tells us that the solutions are of the form

x = \frac{-b\pm \sqrt[]{b^2-4ac}}{2a}.

Note that square root, over the reals, tells us that the are only real solutions if b^2-4ac \geq 0. If that is not the case, say it's negative, the solution are complex. Then, the solutions are of the form

x = \frac{-b \pm i \sqrt[]{4ac-b^2}}{2a}. NOte that this means that if we have a complex number of the form a+bi that is a solution, then the number a-bi (who is called the complex conjugate) is also a solution.

Recall that when we have a polynomial f(x) whose a zero is the number c, then we can factor f as follows f(x) = (x-c) * p(x) where p(x) is another polynomial of lesser degree .

So far, we know that -3 and 4-i are zeros of the function f. Note that we are missing two zeros. But, since complex numbers are zeros of polynomial only by pairs (that is the number and its conjugate are zeros), then, we must have that one of the missing 2 zeros is a real number. We have 4-i as a zero, then, its complex conjugate must be also a zero, i.e 4+i is a zero.

8 0
3 years ago
Please help give bralienst not need explation
Alecsey [184]

Answer:

4.5 cm

Step-by-step explanation:

The ruler says it all..... (why do you need help with this? What grade????)

Hope this helps, have a good day :)

7 0
3 years ago
Read 2 more answers
Ann prefers ice cream cups. Ben and Clay prefer ice cream sandwiches. The cafeteria manager puts one coupon for an ice cream cup
son4ous [18]
D. 2/3 I think:)
Hope this helps.
8 0
3 years ago
Three dice are rolled. Let the random variable x represent the sum of the 3 dice. By assuming that each of the 63 possible outco
tamaranim1 [39]
<h3>Answer:  1/8</h3>

In decimal form, 1/8 = 0.125 which converts to 12.5%

==================================================

Work Shown:

The 63 should be 6^3. There are 6 choices per slot, and 3 slots, so 6^3 = 216 different outcomes.

Here are all of the ways to add to 11 if we had 3 dice

  1. sum = 1+4+6 = 11
  2. sum = 1+5+5 = 11
  3. sum = 1+6+4 = 11
  4. sum = 2+3+6 = 11
  5. sum = 2+4+5 = 11
  6. sum = 2+5+4 = 11
  7. sum = 2+6+3 = 11
  8. sum = 3+2+6 = 11
  9. sum = 3+3+5 = 11
  10. sum = 3+4+4 = 11
  11. sum = 3+5+3 = 11
  12. sum = 3+6+2 = 11
  13. sum = 4+1+6 = 11
  14. sum = 4+2+5 = 11
  15. sum = 4+3+4 = 11
  16. sum = 4+4+3 = 11
  17. sum = 4+5+2 = 11
  18. sum = 4+6+1 = 11
  19. sum = 5+1+5 = 11
  20. sum = 5+2+4 = 11
  21. sum = 5+3+3 = 11
  22. sum = 5+4+2 = 11
  23. sum = 5+5+1 = 11
  24. sum = 6+1+4 = 11
  25. sum = 6+2+3 = 11
  26. sum = 6+3+2 = 11
  27. sum = 6+4+1 = 11

There are 27 ways to add to 11  using 3 dice. This is out of 216 total outcomes of 3 dice being rolled.

So, 27/216 = (1*27)/(8*27) = 1/8 is the probability of getting 3 dice to add to 11.

7 0
3 years ago
Write an equation for the translation of x^2+y^2=25 by 7 units left and 2 units down
soldi70 [24.7K]
Your equation is a circle where the center is the origin (0, 0) and the radius is 5. With the translation, the new center is (- 7, - 2). Radius stays the same. 

Your new equation is:

(x + 7)² + (y + 2)² = 25
4 0
3 years ago
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