The equation above can be used to calculate the volume V, of a cone with a height h and radius r.

A water delivery truck is filling the water tank at Morgan's house. The truck arrived with 2400 L of water. The number of liters

Luda [366]

Answer:

11.81 minutes

Step-by-step explanation:

Here is a simple step-by-step explaination of how to solve this word problem:

Since the truck has 2,400L in it to begin with, the first part of our equation will be 2,400L

$L = 2400L

$

Next we know that the water in the truck decreases at a rate of 110L/min, or Liters per minute.

So we will put that in the equation:

$L = -110L + 2400L$

Now that we have our equation set up, its time to solve.

To figure out how much water it needs to lose in total to end up with 1100 L left, we subtract 1,100 from 2,400.

$2,400 - 1,100= 1,300

$

Now we can take that number and divide it by how many liters per minute were lost.

$1,300/110=11.81$

So the total amount of time it took for the truck to have 1,100 L left is 11.81 minutes. Your answer would be

B. $L=-110t + 2400, t=11.8$ min

Hope this helps! : )

3 0

2 years ago

Read 2 more answers

PLEASE HELPPP MEEEEEEEEEEEEEEE

Papessa [141]

The answer would be

4d+2.75p=12

7 0

3 years ago

Read 2 more answers

Maths!

Ber [7]

Answer:

(1) Variance = 4.5 and Standard deviation = 2.121.

(2) Variance = 4.5 and Standard deviation = 2.121.

(3) The effect on the measure of dispersion if each value is changed uniformly is that it remains unchanged.

Step-by-step explanation:

We are given with the following set of data below;

X $X-\bar X$ $(X-\bar X)^{2}$

5 5 - 8 = -3 9

8 8 - 8 = 0 0

10 10 - 8 = 2 4

9 9 - 8 = 1 1

6 6 - 8 = -2 4

Total 72 36

Firstly, the mean of the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{72}{9}$ = 8

(1)Now, the variance of the given data is;

Variance = $\frac{\sum (X-\bar X)^{2} }{n-1}$

= $\frac{36}{9-1}$ = 4.5

So, the standard deviation, (S.D.) = $\sqrt{\text{Variance}}$

= $\sqrt{4.5}$ = 2.12

(2) Now, each value is added by 2; so the new data set is given by;

X $X-\bar X$ $(X-\bar X)^{2}$

7 7 - 10 = -3 9

10 10 - 10 = 0 0

12 12 - 10 = 2 4

11 11 - 10 = 1 1

8 8 - 10 = -2 4

Total 90 36

Firstly, the mean of the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{90}{9}$ = 10

(1)Now, the variance of the given data is;

Variance = $\frac{\sum (X-\bar X)^{2} }{n-1}$

= $\frac{36}{9-1}$ = 4.5

So, the new standard deviation, (S.D.) = $\sqrt{\text{Variance}}$

= $\sqrt{4.5}$ = 2.12

(3) The effect on the measure of dispersion if each value is changed uniformly is that it remains unchanged as we see in the case of variance or standard deviation.

4 0

3 years ago

In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

so

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

2 years ago

(7×25)+(7×12) in a shorter way

Galina-37 [17]

Answer:

Th answer is 175 + 84 =259

Step-by-step explanation:

follow the PEMDAS procedure multiply in the parentheses then add your 2 answers

7 0

2 years ago