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Nonamiya [84]
3 years ago
11

Select all of the below statements that accurately describe the proper Lewis structure for CBr2F2.- The formal charge on each br

omine is -1.- There are 12 lone pairs of electrons on the molecule.- The formal charge on carbon is zero.- There are 4 covalent bonds within the molecule.- The formal charge on each fluorine is -1.

Chemistry
1 answer:
Yuri [45]3 years ago
6 0

Answer:

There are 12 lone pairs of electrons on the molecule.

The formal charge on carbon is zero.

There are 4 covalent bonds within the molecule.

Explanation:

The formal charge(FC) can be calculated by the equation:

FC = V - N - B/2, where V is the number of the valence electrons of the neutral element, N is the number of non-bonding valence electrons, and B is the total of electrons shared in bond.

The Lewis structure is represented in the image below. F and Br have 7 valence electrons and C 4 valence electrons.

So, for C, FC = 4 - 0 - 8/2 = 0

For the both Br, FC = 7 - 6 - 2/1 = 0

For the both F, FC = 7 - 6 - 2/1 = 0

For the structure, we can see that there are 12 lone pairs of electrons on the molecule (3 in each Br and 3 in each F).

All the bonds are covalent because the atoms are sharing a pair of electrons, so there are 4 covalent bonds within the molecule.

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spoon

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musickatia [10]
The correct answer is option D. i.e. <span>pressure, temperature, or concentration.

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3 years ago
A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in
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Answer:

3.6667

Explanation:

<u>For helium gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

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V₂ = 9.0 L

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Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{5.6}\times {3.0}={P_2}\times {9.0} atm

{P_2}=\frac {{5.6}\times {3.0}}{9.0} atm

{P_1}=1.8667\ atm

<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>

<u>For Neon gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{3.6}\times {4.5}={P_2}\times {9.0} atm

{P_2}=\frac {{3.6}\times {4.5}}{9.0} atm

{P_1}=1.8\ atm

<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>

<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>

6 0
3 years ago
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Answer:

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3 0
3 years ago
Read 2 more answers
A 2.16-g sample of an oxide of chromium contains 1.34 g of chromium. Calculate the simplest formula for the compound.
fomenos

Answer:

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Explanation:

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mass:1.34g                                                       0.82

RAM:52                                                            16

divide the mass with the RAM

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divide by smallest number to find ratio

1                                                                             2

ratio of chromium to oxygen=1:2

8 0
4 years ago
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