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hoa [83]
3 years ago
10

What is the density of lithium metal (in g/cm3) if a cube measuring 0.82 cm × 1.45 cm × 1.25 cm has a mass of 0.794 g?

Chemistry
2 answers:
Maksim231197 [3]3 years ago
7 0
Density is given by mass divided by the volume of a substance.
In this case the mass is 0.794 g and the volume is 0.82 cm ×1.45 cm ×1.25 cm = 1.48625 cm³. 
Therefore, density = 0.794/ 1.48625
                              = 0.5342 g/cm³
 Thus, the density of lithium metal is 0.5342 g/cm³
11Alexandr11 [23.1K]3 years ago
5 0
First, determine the volume of the rectangular prism by multiplying its base, height, and width. That is,

   Volume = Height x weight x length

Substituting the known values,

     Volume = (0.82 cm)(1.45 cm)(1.25 cm) = 1.48625 cm³. 

For calculation of the density, we divide the given mass by the total volume.
    Density = 0.794 g/1.48625 cm³.

Answer: 0.534 g/cm³
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Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of
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Answer:

[H₂] = 1.61x10⁻³ M

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Kc = 9.30x10⁻⁸ = \frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}

First we <u>calculate the initial concentration</u>:

0.45 molH₂S / 3.0L = 0.15 M

The concentrations at equilibrium would be:

[H₂S] = 0.15 - 2x

[H₂] = 2x

[S₂] = x

We <u>put the data in the Kc expression and solve for x</u>:

\frac{(2x^2) * x}{(0.15-2x)^2}=9.30x10^{-8}

\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}

We make a simplification because x<<< 0.0225:

\frac{4x^3}{0.0225} =9.30*10^{-8}

x = 8.058x10⁻⁴

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Read 2 more answers
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