![\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%7Bn%7D%3C%20%5Csqrt%7B2n%2B5%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsquaring%20both%20sides%7D%7D%7Bn%3C%202n%2B5%7D%5Cimplies%200%5Cleqslant%202n%20-%20n%20%2B%205%20%5C%5C%5C%5C%5C%5C%200%20%3C%20n%2B5%5Cimplies%20%5Cboxed%7B-5%20%3C%20n%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B-5%5Cleqslant%20n%20%3C%202%7D%7B%5Cboxed%7B-5%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B3em%7D%7B0.25pt%7D2%7D)
namely, -5, -4, -3, -2, -1, 0, 1. Excluding "2" because n < 2.
Matching each equation of the plecewise function represented in the graph will be:
- 2 < x < 3 = 3 - x
- 0 < x < 2 = 1
- x = 2 = x
- 3 < x < 5 = 5 - x
<h3>How to illustrate the information?</h3>
It should be noted that a domain simply means the set of inputs that are accepted by the function.
In this case, the equation of the piecewise function represented is given.
The graph is attached.
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The equasion she would use would be 60,000 = 1000x + 40,000
this would means 1,000 times a number plus the 40,000 shes already getting equals 60,000
By definition, supplementary angles are those whose sum is 180°
Therefore, ∠2 = 180 - ∠1
2x + 4 = 180 - 124
2x = 52
x = 26°
Answer:
g=79
h=55
j=75
Step-by-step explanation:
1. When a transversal intersects two parallel lines corresponding angles, angles that are located in the same relative position an intersection of transversal and two or more straight lines, are congruent. Therefore g=79.
2. Since the two lines are parallel same side interior angles are supplementary. This means they add up to 180. So to find h solve the equation h+125=180. Once solved you get 55.
3. Like question 2, these angles are same side interior and therefore supplementary. To find j solve the equation j+105=180, which gets j=75.
