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sdas [7]
3 years ago
7

Please help! I need the work for this.

Mathematics
1 answer:
Elden [556K]3 years ago
7 0

Answer:

Step-by-step explanation:

x = 6 hope this helps

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PLEASE HELP ASAP 15 BRAINLY POINTS
lana66690 [7]

Answers

1) 1

2) 11

3) 4

4) D) Yes, the constant of variation is 3

Explanation

Q1

The slope of a line is given by

Slope = (change in y)/(change in x)

= (0 - -2)/(-4 - -6)

= 2/2

= 1

Q2

Slope = Δy/Δx

= (8 - -3)/(2 - 1)

= 11/1

= 11

Q3

Y varies directly as X. This is written as,

Y ∞ X

Put and equal sign then introduce the constant of proportionality, K.

Y = KX

K = Y/X

K = 6/18 = 1/3

∴ Y = (1/3)X

Y = (1/3) × 12

Y = 4

Q4

32Y = 96X

Dividing both sides by 32,

Y = 96/32 X

Y = 3X

3 been the constant, Y varies directly as X.

So, the equation 32y = 96x is a direct variation.

Constant of variation = 3

5 0
3 years ago
Read 2 more answers
How to solve problem
sergey [27]
Your equation would be 2x - 12 + 3x - 15 = 23
Combine like terms and solve for x
6 0
3 years ago
Please help as soon as possible
MAVERICK [17]

Answer: Your Answer is: -8/17

7 0
3 years ago
How many 7-digit numbers can be
padilas [110]

Answer: 5040 7-digit numbers

Step-by-step explanation:

Permutations:

1: 1 ==> 1 permutation ==> 1 ==> 1!

12: 12, 21 ==> 2 permutations ==> 1*2 ==> 2!

123: 123, 132, 213, 231, 312, 321 ==> 6 permutations ==> 1*2*3 ==> 3!

7-digits: 7!=

1*2*3*4*5*6*7=5040 7-digit numbers

4 0
2 years ago
Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)
Sloan [31]
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b... 

<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>

<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>

<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
7 0
4 years ago
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